c# programming doubt

Question

hello all the following code is not working as expected CODE Console.WriteLine(enter alphabet); int c = Console.Read(); Console.WriteLine(c); Console.WriteLine(enter string); string j = Console.ReadLine(); Console.WriteLine(j); Console.ReadKey(); it doesn't allow to enter the string and just exits the program but if code is reversedit works fine Console.WriteLine(enter string); string j = Console.ReadLine(); Console.WriteLine(j); Console.WriteLine(enter alphabet); int c = Console.Read(); Console.WriteLine(c); Console.ReadKey(); can anyone explain this??

Vithal Wadje · Answer

this is code Console.WriteLine(enter alphabet); int c = Console.Read(); Console.WriteLine(c); Console.ReadLine(); Console.WriteLine(Enter string); string j = Console.ReadLine(); Console.WriteLine(Your Entered String is :+j); Console.ReadLine(); this is output

Maha · Answer

Problem with the Console.Read() method. It is explained in following website: http://www.dotnetperls.com/console-read 'Note: When the Read method is first called it blocks execution waiting for the input to be sent by the terminal window'. You can alter the program as follows: using System; class Program { static void Main(string[] args) { Console.Write(Enter alphabet ); char c = char.Parse(Console.ReadLine()); int x = Convert.ToInt32(c); Console.WriteLine(x); Console.Write(Enter string ); string j = Console.ReadLine(); Console.WriteLine(j); Console.ReadKey(); } }

Ajay Yadav · Answer

The Console.Read() methods constantly reads the data and buffers won't ends until some method explicitly ends it. Hence here one more Console.ReadLine() impose and extra ENTER to terminate the existing buffer... Console.WriteLine(enter alphabet); int c = Console.Read(); Console.WriteLine(c); Console.ReadLine(); Console.WriteLine(enter string); string j = Console.Read().ToString(); Console.WriteLine(j); Console.ReadLine();

Wim Sturkenboom · Answer

Whatever you type goes in the keyboard buffer; this includes the (being one or two characters). Console.Read() reads one character from the keyboard buffer; but the buffer contains both the character(s) that you typed and the . So the next character stays (or next characters stay) in the buffer. Next you're reading input again (using Console.ReadLine()); this reads the buffer up to (and including) the . after that the keyboard buffer will be empty. Note that Console.ReadLine() will strip the . You can test by typing abc after the first prompt. You will get 'a' (97) back for the first read and 'bc' for the second read. // edit: correct little mistake in first paragraph

Aravind Chitra · Answer

sorry for the unclear question.I am referring to my original question.code 1 gives wrong result but code 2 gives the correct answer..

Vithal Wadje · Answer

i have not changed any order i have just added Console.ReadLine(); because its require while reading the any line from console

Aravind Chitra · Answer

thanksthe code serves the purpose.But any idea why the same codes as mentioned by me give varying results when order is changed...

Aravind Chitra · Answer

no still not working.the string entered is not displayed

Aravind Chitra · Answer

in the first case  the output window is like enter alphabet a 97 enter string then it exits in the second casethe output is like enter string haha haha enter alphabet a 97

Vithal Wadje · Answer

use this codeits working Console.WriteLine(enter alphabet); int c = Console.Read(); Console.WriteLine(c); Console.WriteLine(enter string); string j = Console.ReadLine(); Console.ReadLine(); Console.WriteLine(j); Console.ReadKey(); Console.ReadLine();

Vithal Wadje · Answer

on which line line the screen exit ?

Aravind Chitra · Answer

thank you for the quick reply butthat doesn't solve the problem

Vithal Wadje · Answer

instead of console.Readkey() Use console.Readline()