C# Question

Question

Please provide the c# codes to find if a number is peterson number or not. Peterson number means the sum of individual factorials of the number is equal to the
number itself,e.g 143 is a peterson no. because 1!+4!+5!=145

Vulpes · Answer

Try this: using System; class Peterson { static void Main() { Console.Write(Enter a number : ); int n = int.Parse(Console.ReadLine()); int temp = n; int digit fact = 1 sum = 0; while(temp > 0) { digit = temp % 10; for(int i = 1; i sum += fact; fact = 1; temp /= 10; } if (n > 0 && n == sum) { Console.WriteLine({0} is a Peterson number n); } else { Console.WriteLine({0} is not a Peterson number n); } Console.ReadKey(); } }

Anurag Sarkar · Answer

I am providing you the logic void main() { int ncs=0mif=1; Console.WriteLine(ENTER A VALUE : ); int n=int.Parse(Console.Readline()); m=n; while(n>o) { c=n%10; for(i=0;i f=f*i; s=s+f; f=1; n=n/10; } if(s==m) { Console.WriteLine(
 THE ENTERED NUMBER IS PETERSON NUMBER.); Console.ReadLine(); } else { Console.WriteLine(
 THE ENTERED NUMBER IS NOT A PETERSON NUMBER.); Console.ReadLine(); }

Nilesh Sanyal · Answer

Thank u very much