Check for an Integer Value-Without Exception

Question

Hello all I want to multiply a number by itselfand the number must be Integer.A program when i get the input number as a string it wont take it as the input n it will show an error You are not entered Integertry with some other number.(Without use of exceptions)Is there any possiblity? i have written one code.But it shows an exception at run time. int number=int.parse(console.ReadLine()); if (number = int.MinValue) { Console.Write(
 Enter the number :); number *= number; Console.WriteLine(number); } else { Console.WriteLine(You are not entered Integertry with some other number); } Whats wrong with my code?How will i write the code only it will accept Integers not an decimal or string. or Some Clues to do it.I will find out the way. As am learner i want to know the things. Thanks.

Manuel · Answer

Also you should check Math.Abs( numer ) because you would get an negative number if you would get a larger number than int.MaxValue

Alan · Answer

If you have .NET 2.0 then using the int.TryParse() method will enable you to do this without throwing an exception: int number; bool isValid = false; do { Console.Write(
 Enter the number : ); isValid = int.TryParse(Console.ReadLine() out number); if (isValid) break; Console.WriteLine(
 You have not entered an integer try with some other number); } while(!isValid); number *= number; Console.WriteLine(
 The square of your number is {0}number); Notice that you never need to check whether an int lies between its minimum and maximum values. As long as it is an 'int' it must do :)