Check Whether Button Clicked or not - Please Help

Question

Hi all I am creating an Windows application. I have 2 forms. In First form I have two buttons. The Second Buttons Enabled property is set to False. If the First button is clicked then Form 2 should be shown which I have done with the Coding. In the second Form I have one button If this button is clicked then it should show first form and the second button of that form should be enabled (Enabled property to be set to TRUE). Can anyone help me out in doing this task? Please help me out. Thanks in advance!!

sachi vasishta · Answer

Hi sheetal Assuming that you have set the button2's enabled property of form1 to false First set the button2's modifier property to public in form1 then write the following code for button1 click event of form1 private void button1_Click( object sender EventArgs e) { Form2 myform = new Form2 ( this ); myform.Show(); } private void button2_Click( object sender EventArgs e) { MessageBox .Show( Hi Sachi ); } Then write the following code under the form2's constructor and button1 click event public partial class Form2 : Form { Form1 form1; public Form2( Form1 f1) { InitializeComponent(); this .form1 = f1; } private void button1_Click( object sender EventArgs e) { this .Dispose(); form1.button2.Enabled = true ; } } Hope this helps

Jon Bellamy · Answer

Hi Sheetal You can do it this way. Set in the click event of the button for form 2 the following: this.DialogResult = true; Then in your calling code from button 1 of form one type Form2 myForm2 = new Form2(); if (myForm2.ShowDialog().Value) { this.Button2.IsEnabled = true; } This will then only enable it if button1 on form2 is pressed. Hope that helps - Jon