create patten using C#

Question

1 2 3 4 12 13 14 5 11 16 15 6 10 9 8 7 make spiral in C# console application. can any one provide code?

Vulpes · Answer

This code will draw that particular spiral: using System; class Spiral { static void Main() { for (int i = 1 ; i { Console.Write({02}  i); } Console.WriteLine(); for (int i = 12; i { Console.Write({02}  i); } Console.WriteLine( 5); Console.Write(11 ); for (int i = 16; i >= 15; i--) { Console.Write({02}  i); } Console.WriteLine( 6); for (int i = 10; i >= 7; i--) { Console.Write({02}  i); } Console.ReadKey(); } }

Vulpes · Answer

Here's some more general code for drawing a spiral like the one you posted except that the number of rows and columns can vary: using System; class Spiral { static void Main() { Console.Write(Enter no of rows : ); int rows = int.Parse(Console.ReadLine()); Console.Write(Enter no of columns : ); int cols = int.Parse(Console.ReadLine()); Console.WriteLine(); int[] matrix = new int[rows cols]; FillMatrix(matrix 1 0); PrintMatrix(matrix); Console.ReadKey(); } static void FillMatrix(int[] matrix int startNum int startRow) { int rows = matrix.GetLength(0); int cols = matrix.GetLength(1); int maxNum = rows * cols; int startCol = startRow; for(int i = startCol; i { matrix[startRow i] = startNum++; } if (startNum > maxNum) return; for(int j = startRow + 1; j { matrix[j cols - startCol - 1] = startNum++; } if (startNum > maxNum) return; for(int j = cols - startCol - 2; j >= startCol; j--) { matrix[rows - startRow - 1 j] = startNum++; } for(int j = rows - startRow - 2; j >= startRow + 1; j--) { matrix[j startCol] = startNum++; } if (startNum } static void PrintMatrix(int[] matrix) { int rows = matrix.GetLength(0); int cols = matrix.GetLength(1); for(int i = 0; i { for(int j = 0; j { Console.Write({0 4} matrix[i j]); } Console.WriteLine(); } } }

Nanhe Siddique · Answer

using System; public class MatrixSpiral { static void Main() { Console .Write( N =  ); int n = int .Parse( Console .ReadLine()); int [] matrix = new int [n n]; FillMatrix(matrix n); PrintMatrix(matrix n); } private static void FillMatrix( int [] matrix int n) { int positionX = n / 2; // The middle of the matrix int positionY = n % 2 == 0 ? (n / 2) - 1 : (n / 2); int direction = 0; // The initial direction is down int stepsCount = 1; // Perform 1 step in current direction int stepPosition = 0; // 0 steps already performed int stepChange = 0; // Steps count changes after 2 steps for ( int i = 0; i { // Fill the current cell with the current value matrix[positionY positionX] = i; // Check for direction / step changes if (stepPosition { stepPosition++; } else { stepPosition = 1; if (stepChange == 1) { stepsCount++; } stepChange = (stepChange + 1) % 2; direction = (direction + 1) % 4; } // Move to the next cell in the current direction switch (direction) { case 0: positionY++; break ; case 1: positionX--; break ; case 2: positionY--; break ; case 3: positionX++; break ; } } } private static void PrintMatrix( int [] matrix int n) { for ( int i = 0; i { for ( int j = 0; j { Console .Write( {03}  matrix[i j]); } Console .WriteLine(); } } }