creating a new form instance with Application.Run

Question

I'm wondering why the following line of code is valid: Application.Run(new MyForm()); (Assuming the class MyForm exists) Does this result in the creation of a new instance of the MyForm class? If so, why don't you have to give the instance a name? I would expect you would have to do the following: private MyForm MyFormInstance; then, later... Application.Run(MyFormInstance = new MyForm()); Thanks. Diluter

bilnaad · Answer

What you want to do is not valid. But you could do this: Form form = new Form(); --end later Application.Run(form); It's not important if the object reference already exists somewhere. You just need to pass in a form reference. That's it! How you pass it in .... that's your choice ^_^

dmosborne · Answer

"There is no need to store the object in a variable when it's not used afterwards." Then is there any benefit to do it this way?: private MyForm MyFormInstance; then, later... Application.Run(MyFormInstance = new MyForm()); Thanks. Diluter

bilnaad · Answer

Application.Run() creates a messageloop for the form passed in it. The loop won't exit until a quitmessage has been send. You don't have to "give it a name". There is no need to store the object in a variable when it's not used afterwards. So you can pass the newly created object directly into the method. This is also common in creating arrays. ex: decimal[] decs = new decimal[]{new decimal(1) ,new decimal(2) ,new decimal(3)}; The references to the objects is stored directly into the array. I hope this helps you understand it some more ^_^

creating a new form instance with Application.Run

Answers (3)