data writing from multiple controls in same file

Question

dear i have this code

StreamWriter stname = new StreamWriter("d:\\abc.text");
            string text = t11.Text;
            stname.WriteLine(text);
            stname.Close();

            StreamWriter stno = new StreamWriter("d:\\abc.text");
            string no = lpnu1.Text;
            stno.WriteLine(no);
            stno.Close();

but in output file only no is written there is no name .but if i remove stno streamwriter then it writes name.
how i can write both name and no in same file.both these are on button click event. i not know much c#.

Vulpes · Answer

Taking the second problem first you need to always specify true as the second argument to the StreamWriter constructor. This will create the file if it doesn't already exist or append to it if it does exist. To deal with that and the first problem make the highlighted changes as follows: private void pt_Click(object sender EventArgs e) { StreamWriter date = new StreamWriter(d:\abc.text  true ); string dates = Convert.ToString(dp1.Value) +   ; date.Write(dates); date.Close(); StreamWriter stno = new StreamWriter(d:\abc.texttrue); string no = lpnu1.Text +   ; stno.Write(no); stno.Close(); StreamWriter stname = new StreamWriter(d:\abc.text true); string text = t11.Text +   ; stname.WriteLine(text); // make sure next entries will start on a new line stname.Close(); // button1.Hide(); // pt.Hide(); MessageBox.Show(data is printed); }

Vulpes · Answer

Change this line: StreamWriter stno = new StreamWriter(d:\abc.text); to: StreamWriter stno = new StreamWriter(d:\abc.text true); The StreamWriter will now append to the file rather than overwriting it.

Vulpes · Answer

To print a windows form you first need to capture the image of the form from the desktop and then print that. There's some code here on MSDN which shows how to do this: http://msdn.microsoft.com/en-us/library/6he9hz8c.aspx To allow specifically for A4 paper and to catch the exception if something goes wrong when attempting to print you'll need to change the printButton_Click handler as follows: void printButton_Click(object sender EventArgs e) { try { CaptureScreen(); PaperSize ps = new PaperSize(); ps.RawKind = (int)PaperKind.A4; printDocument1.DefaultPageSettings.PaperSize = ps; printDocument1.Print(); } catch(Exception ex) { MessageBox.Show(ex.Message); } }

ta mu · Answer

finally know i want to print the form(form1) but explicitly means without apearing a dialog. when print button is pressed a printout comes out of printer. but no printer is installed with my pc. exception handling for printer is necessery.. i want to print of size a4

ta mu · Answer

thanks dear because its my first application therefor i m questioning for such simple things.

ta mu · Answer

1) thanks dear but know i want to frormate text as in output file dta is in formate datenoname means no space between them but i want ( date no name) code is again private void pt_Click(object sender EventArgs e) { StreamWriter date = new StreamWriter(d:\abc.text ); string dates = Convert.ToString(dp1.Value); date.Write(dates); date.Close(); StreamWriter stno = new StreamWriter(d:\abc.texttrue); string no = lpnu1.Text; stno.Write(no); stno.Close(); StreamWriter stname = new StreamWriter(d:\abc.text true); string text = t11.Text; stname.Write(text); stname.Close(); // button1.Hide(); // pt.Hide(); MessageBox.Show(data is printed); } sesond problem is when i close aplication my data is in file but when run it again and enter data my old data get lost but i whant evry time whenever i enter data all data remain in file.