Differntiate the type of card like credit or debit card

Question

How to get the type of card like debit card or credit card using card number.. are there any regular expressions like we have for types of credit cards? 
Thanks in advance

Answer 1

Thank you for your valuable reply , i'll  try this solution in my project ..

Answer 2

Hi Can you try this too,

public static string Serialize(object dataToSerialize)     {         if(dataToSerialize==null) return null;          using (StringWriter stringwriter = new System.IO.StringWriter())         {             var serializer = new XmlSerializer(dataToSerialize.GetType());             serializer.Serialize(stringwriter, dataToSerialize);             return stringwriter.ToString();         }     }      public static T Deserialize<T>(string xmlText)     {         if(String.IsNullOrWhiteSpace(xmlText)) return default(T);          using (StringReader stringReader = new System.IO.StringReader(xmlText))         {             var serializer = new XmlSerializer(typeof(T));             return (T)serializer.Deserialize(stringReader);         }     }

Answer 3

Hi Good day,

Suppose I have a collection 

List<Employee> empList = new List<Employee>();

            empList.Add(new Employee() { ID = 1, FName = "John", LName = "Shields", DOB = DateTime.Parse("12/11/1971"), Sex = 'M' });

            empList.Add(new Employee() { ID = 2, FName = "Mary", LName = "Jacobs", DOB = DateTime.Parse("01/17/1961"), Sex = 'F' });

            empList.Add(new Employee() { ID = 3, FName = "Amber", LName = "Agar", DOB = DateTime.Parse("12/23/1971"), Sex = 'M' });

            empList.Add(new Employee() { ID = 4, FName = "Kathy", LName = "Berry", DOB = DateTime.Parse("11/15/1976"), Sex = 'F' });

            empList.Add(new Employee() { ID = 5, FName = "Lena", LName = "Bilton", DOB = DateTime.Parse("05/11/1978"), Sex = 'F' });

            empList.Add(new Employee() { ID = 6, FName = "Susanne", LName = "Buck", DOB = DateTime.Parse("03/7/1965"), Sex = 'F' });

            empList.Add(new Employee() { ID = 7, FName = "Jim", LName = "Brown", DOB =DateTime.Parse("09/11/1972"), Sex = 'M' });

            empList.Add(new Employee() { ID = 8, FName = "Jane", LName = "Hooks", DOB = DateTime.Parse("12/11/1972"), Sex = 'F' });

            empList.Add(new Employee() { ID = 9, FName = "Robert", LName = "", DOB =DateTime.Parse("06/28/1964"), Sex = 'M' });

            empList.Add(new Employee() { ID = 10, FName = "Cindy", LName = "Fox", DOB = DateTime.Parse("01/11/1978"), Sex = 'M' });


Code to convert to xml

var xEle = new XElement("Employees",

                from emp in empList

                select new XElement("Employee",

                             new XAttribute("ID", emp.ID),

                               new XElement("FName", emp.FName),

                               new XElement("LName", emp.LName),

                               new XElement("DOB", emp.DOB),

                               new XElement("Sex", emp.Sex)

                           ));