Encryption between C and C#

Question

Can anyone help me for writing the program of encryption and decryption in C and C#. I want same result after encrypt in C and decrypt in C#.

rajat kumar · Answer

Try the code- C : #include #include static char encoding_table [] = { 'A'  'B'  'C'  'D'  'E'  'F'  'G'  'H'  'I'  'J'  'K'  'L'  'M'  'N'  'O'  'P'  'Q'  'R'  'S'  'T'  'U'  'V'  'W'  'X'  'Y'  'Z'  'a'  'b'  'c'  'd'  'e'  'f'  'g'  'h'  'i'  'j'  'k'  'l'  'm'  'n'  'o'  'p'  'q'  'r'  's'  't'  'u'  'v'  'w'  'x'  'y'  'z'  '0'  '1'  '2'  '3'  '4'  '5'  '6'  '7'  '8'  '9'  '+'  '/' }; static char * decoding_table = NULL ; static int mod_table [] = { 0  2  1 }; char * base64_encode ( const unsigned char * data  size_t input_length  size_t * output_length ) { * output_length = 4 * (( input_length + 2 ) / 3 ); char * encoded_data = malloc (* output_length ); if ( encoded_data == NULL ) return NULL ; for ( int i = 0  j = 0 ; i input_length ;) { uint32_t octet_a = i input_length ? ( unsigned char ) data [ i ++] : 0 ; uint32_t octet_b = i input_length ? ( unsigned char ) data [ i ++] : 0 ; uint32_t octet_c = i input_length ? ( unsigned char ) data [ i ++] : 0 ; uint32_t triple = ( octet_a 0x10 ) + ( octet_b 0x08 ) + octet_c ; encoded_data [ j ++] = encoding_table [( triple >> 3 * 6 ) & 0x3F ]; encoded_data [ j ++] = encoding_table [( triple >> 2 * 6 ) & 0x3F ]; encoded_data [ j ++] = encoding_table [( triple >> 1 * 6 ) & 0x3F ]; encoded_data [ j ++] = encoding_table [( triple >> 0 * 6 ) & 0x3F ]; } for ( int i = 0 ; i mod_table [ input_length % 3 ]; i ++) encoded_data [* output_length - 1 - i ] = '=' ; return encoded_data ; } and decrypt in C#: byte [] data = Convert . FromBase64String ( encodedString ); string decodedString = Encoding . UTF8 . GetString ( data ); Hope this will help you.