Exception Handling

Question

Exception Handling - Finally block

VTA Technologies is planning to conduct a Walk-in interview. The interview has 4 levels. To attend the interview, the candidates need to register the following information:
Name, Age, Expected salary and Gender. The age limit for the candidates is between 18 and 50.

Develop a console application to implement the above given scenario.

Use exception handling to validate age and salary of the candidate. If the candidate’s age is less than 18 or greater than 50 throw a user defined exception as AgeException and display the message “Registration Failed. Age should be greater than 18 and less than 50". If candidate’s age is between 18 and 50, then get the other information (Salary and Gender).

Likewise, if the candidate’s expected salary is less than or equal to 0 throw a user defined exception as SalaryException, then display the message as “Registration Failed. Salary cannot be a negative number”. If the salary is not a negative number, then get the Gender details and display the message as “Registration Successful”. Irrespective of whether the registration is successful or not, print the message “Best Wishes”.

Sample Input/output Statements:

Enter the Name:Rahul
Enter the Age:35
Enter the Salary:25000
Enter the Gender(f/m):m
Rahul
35
m
Registration Successful
Best Wishes

Sample Input/output Statements:

Enter the Name:Rahul
Enter the Age:15
Registration Failed. Age should be greater than 18 and less than 50
Best Wishes

Aman · Answer

I am attaching the Solution file . Go through this and if you have any query feel free to ask. and please accept it as an answer if it helps.

Arjunan Selvam · Answer

Define the custom exceptions as follows.As per your requirement i have defined the AgeException and SalaryException. Age Exception: using System; using System.Runtime.Serialization; namespace Csharpcorner.Demo.CustomExceptions { class AgeException : Exception { public AgeException() : base() { } public AgeException(String message) : base(message) { } public AgeException(String message Exception innerException) : base(message innerException) { } protected AgeException(SerializationInfo info StreamingContext context) : base(info context) { } } } Salary Exception: using System; using System.Runtime.Serialization; namespace Csharpcorner.Demo.CustomExceptions { class SalaryException : Exception { public SalaryException() : base() { } public SalaryException(String message) : base(message) { } public SalaryException(String message Exception innerException) : base(message innerException) { } protected SalaryException(SerializationInfo info StreamingContext context) : base(info context) { } } } You can check the conditions in the properties as follows. using csharpcorner.Demo.CustomExceptions; namespace Csharpcorner.Demo { public class Register { private string _name; private int _age; private int _salary; private char _gender; public string Name { get { return _name; } set { _name = value; } } public int Age { get { return _age; } set { if (value 50) { throw new AgeException(Registration Failed. Age should be greater than 18 and less than 50); } else { _age = value; } } } public int Salary { get { return _salary; } set { if (value { throw new SalaryException(Registration Failed. Salary cannot be a negative number); } else { _salary = value; } } } public char Gender { get { return _gender; } set { _gender = value; } } } } Main program: using System; namespace Csharpcorner.Demo { class Program { static void Main(string[] args) { try { Register register = new Register(); GetValuesFromUser(register); DisplayUserInfo(register); } catch (Exception ex) { Console.WriteLine(ex.Message); } finally { Console.WriteLine(Best wishes); Console.ReadKey(); } } public static Register GetValuesFromUser(Register userdata) { Console.Write(Enter your name =); userdata.Name = Console.ReadLine(); Console.Write(Enter your age =); userdata.Age = Convert.ToInt32(Console.ReadLine()); Console.Write(Enter your salary =); userdata.Salary = Convert.ToInt32(Console.ReadLine()); Console.Write(Enter your gender =); userdata.Gender = Convert.ToChar(Console.ReadLine()); return userdata; } public static void DisplayUserInfo(Register data) { Console.WriteLine(Name = {0} data.Name); Console.WriteLine(Age = {0} data.Age); Console.WriteLine(Salary = {0} data.Salary); Console.WriteLine(Gender = {0} data.Gender); Console.WriteLine(Registration successful.); } } }

Shilpesh Sinha · Answer

thank you Arjunan Selvan

Shilpesh Sinha · Answer

thank you Aman