Find leader in array in c#

Question

Brijesh Rathor · Answer

you can do like this public class LeadersInArray { static void findTheLeaders(int inputArray[]) { System.out.println(The leaders in +Arrays.toString(inputArray)+ are :); for (int i = 0; i { boolean flag = true; for (int j = i+1; j { if (inputArray[j] > inputArray[i]) { flag = false; break; } } if (flag) { System.out.println(inputArray[i]); } } } public static void main(String[] args) { findTheLeaders(new int[] {12 9 7 14 8 6 3}); findTheLeaders(new int[] {8 23 19 21 15 6 11}); findTheLeaders(new int[] {55 67 71 57 51 63 38}); findTheLeaders(new int[] {21 58 44 14 51 36 23}); } }

Mayank · Answer

#include using namespace std; /*C++ Function to print leaders in an array */ void printLeaders(int arr[] int size) { for (int i = 0; i { int j; for (j = i+1; j { if (arr[i] break; } if (j == size) // the loop didn't break cout } } /* Driver program to test above function */ int main() { int arr[] = {16 17 4 3 5 2}; int n = sizeof(arr)/sizeof(arr[0]); printLeaders(arr n); return 0; } I u think it resolve your query please mark as answer.

Dipika · Answer

void printLeaders( int arr[] int size) { for ( int i = 0; i { int j; for (j = i+1; j { if (arr[i] break ; } if (j == size) // the loop didn't break console.write arr[i] ; } }