Gridview

Question

Hello All How I fill grid 10x 10 with random numbers using random function

Suthish Nair · Answer

Amit already given the logic. So why don't you try with the GridView control? using System.Data; GridView dgv = new GridView(); Random rnd = new Random(); DataTable dt = new DataTable(); DataRow dr; for (int j = 0; j { dt.Columns.Add(new DataColumn()); } for (int i = 0; i { dr = dt.NewRow(); for (int col = 0; col { dr[col] = (int)rnd.Next(1, 10000); } dt.Rows.Add(dr); } dgv.AutoGenerateColumns = true; dgv.DataSource = dt; dgv.DataBind(); PlaceHolder1.Controls.Add(dgv);

hamida khanam · Answer

Hello Thanks Satish for helping and many many thanks to Amit for giving exact core solution to the problem.

Suthish Nair · Answer

thread resolved?

hamida khanam · Answer

Thanks But I had to use it for web application not windows.Can you tell me please how to do it in web applications

Amit Choudhary · Answer

Hi friend, Create a datasource for e.g. datatable fill it with random no's having 10 rows and 10 columns and bind it with your GridView. Below is the example for widows application: private void Form1_Load(object sender, EventArgs e) { DataGridView dgv = new DataGridView(); DataTable dt = new DataTable(); DataRow dr; Random rnd=new Random(); for (int j = 0; j { dt.Columns.Add(new DataColumn()); } for (int i = 0; i { dr = dt.NewRow(); for (int col = 0; col { dr[col] = (int)rnd.Next(1,10000); } dt.Rows.Add(dr); } dgv.DataSource = dt; this.Controls.Add(dgv); } The code in blue is the code to create the DataTable. Please mark "Do you like this answer" if it helps you. Thansk.

Gridview

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