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Normal 0 false false false EN-US X-NONE AR-SA Write complete C++ program that will read three integer values x y and z from keyboard then compute the result of the following expressions. x+'A'%3*y-z x+'A'%3*(y-z)>(x+'A')%3*y-z (x^2+y^2)^1/2 >10&&z++*3 /* Style Definitions */ table.MsoNormalTable {mso-style-name:Table Normal; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:Calibrisans-serif; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:Times New Roman; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:Arial; mso-bidi-theme-font:minor-bidi;}

Vulpes · Answer

I was thinking before that the ^ operator in the third expression was being used to represent exponientation (as in several other languages such as VB) but on reflection I think it's probably being used in its normal C++ sense of the 'exclusive or' operator. So I'd change the program to: #include using namespace std; int main() { int x y z; cout cin >> x; cout cin >> y; cout cin >> z; int result = x + 'A' % 3 * y - z; cout int result2 = x + 'A' % 3 * (y - z) > (x + 'A') % 3 * y - z; cout (x+'A')%3*y-z int result3 = (x ^ 2 + y ^ 2) ^ 1/2 > 10 && z++ * 3 cout 10&&z++*3 return 0; }

Vulpes · Answer

Try: #include #include using namespace std; int main() { int x y z; cout cin >> x; cout cin >> y; cout cin >> z; int result = x + 'A' % 3 * y - z; cout int result2 = x + 'A' % 3 * (y - z) > (x + 'A') % 3 * y - z; cout (x+'A')%3*y-z int result3 = sqrt((double)(x * x + y * y)) > 10 && z++ * 3 cout 10&&z++*3 return 0; }