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Question

write a c++ program that keeps reading integer numbers until a negative number is entered. Then your program prints the average and the maximum of the numbers that are divisible by 5 only.

Vulpes · Answer

Try this: #include using namespace std; int main() { int num max = -1; int n = 0 sum = 0; double avg; cout while(true) { cout cin >> num; if (num if (num % 5 == 0) { n++; sum += num; if (num > max) max = num; } } cout if (n > 0) { avg = (double)sum/n; cout cout } else { cout } return 0; }