How can I deserialize an XML - Windows Phone

Question

I'm using this function to deserialise the data of the xml file:

Uri uri = new Uri("/XML/ligne1_EUROPE.xml", UriKind.Relative);
XDocument document = XDocument.Load("XML/ligne1_EUROPE.xml"); 
XmlSerializer serializer = new XmlSerializer(typeof(Destinataires)); 
Destinataires ArretLoad = (Destinataires)serializer.Deserialize(document.CreateReader());
listBox.ItemsSource = ArretLoad.Collection;

He call the Destinataires class:

[XmlRoot("root")] 
   public class Destinataires 
   { 
      [XmlArray("Destinataires")] 
      [XmlArrayItem("Destinataire")] 
      [XmlArrayItem("Horraires")] 
      [XmlArrayItem("Horraire")] 
      public ObservableCollection<XML_Arret> Collection { get; set; } 
   }
And call the XML_Arret class
 public class XML_Arret 
 { 
   [XmlElement("Designation")] 
   public string Designation { get; set; } 
   [XmlElement("Carre")] 
   public string Carre { get; set; } 
   [XmlElement("Horraires")] 
   public Horraires[] Horaires { get; set; } 
 
   public class Horraires 
   { 
      [XmlElement("Horraire")] 
      public string Horraire { get; set; } 
   } 
}
My XML files is:
<?xml version="1.0" encoding="ISO-8859-1"?> 
<root> 
   <Destinataires> 
      <Destinataire> 
         <Designation>Faubourd d'isle</Designation> 
         <Carre>images/1.png</Carre> 
         <Horraires> 
            <Horraire>6h18</Horraire> 
            <Horraire>6h28</Horraire> 
            <Horraire>6h38</Horraire>           
                  ...       
         </Horraires> 
      </Destinataire>         
         ...   
   </Destinataires> 
</root>
But when I debug my programm, I've this message: 
   Une exception de type 'System.InvalidOperationException' s'est produite dans System.Xml.Serialization.ni.dll 
   mais n'a pas été gérée dans le code utilisateur 
   
   à la ligne: XmlSerializer serializer = new XmlSerializer(typeof(Destinataires));
So, I'm lost, Do you can Help me?
And I'm sorry for my langage, I'm a french person.
Thanks

Vulpes · Answer

Valentin I think the problem here is that your XML attributes are not quite. When I changed them to the following your file deserialized correctly: [XmlRoot(root)] public class Destinataires { [XmlArray(Destinataires)] [XmlArrayItem(Destinataire)] public ObservableCollection Collection { get; set; } } public class XML_Arret { [XmlElement(Designation)] public string Designation { get; set; } [XmlElement(Carre)] public string Carre { get; set; } [XmlArray(Horraires)] [XmlArrayItem(Horraire)] public Horraires[] Horaires { get; set; } public class Horraires { [XmlText] public string Horraire { get; set; } } }

Vulpes · Answer

Glad to hear you've got it working now :)

Valentin Martin · Answer

Hello Vulpes  Thanks for your help !

Ramesh Maruthi · Answer

Valentin Try the Vulpes code its working even for me :) Thanks Vulpes sir :)

Valentin Martin · Answer

Hi I've try with your changement: XmlSerializer deserializer = new XmlSerializer(typeof(DestinatairesList)); TextReader reader = new StreamReader(XML/ligne1_EUROPE.xml); object obj = deserializer.Deserialize(reader); DestinatairesList XmlData = (DestinatairesList)obj; reader.Close(); And for display Destinataire. Designation in my ListBox: listBox1.ItemsSource = XmlData.Destinataire; ??? And: [XmlRoot(Destinataires)] public class DestinatairesList { [XmlElement(Destinataires)] public List Destinataire { get; set; } } public class Destinataire { [XmlElement(Destinataire)] public string DestinatairE { get; set; } [XmlElement(Designation)] public string Designation { get; set; } [XmlElement(Carre)] public string Carre { get; set; } [XmlElement(Horraires)] public List Horaires { get; set; } } public class Horraires { [XmlElement(Horraire)] public string Horaire { get; set; } } But I've a problem: nothing appears on my screen. So I think I've a problem when I sent my data to the ListBox or is in the DestinatairesList or Destinataire.

Ramesh Maruthi · Answer

Faubourd d'isle images/1.png 6h18 6h28 6h38 ... ... [XmlRoot(Destinataires)] public class DestinatairesList { [XmlElement(Destinataire)] public List Destinataires{ get; set; } } public class Destinatarie { [XmlElement(Designation)] public string Designation { get; set; } [XmlElement(Carre)] public string Carre { get; set; } [XmlElement(Horraires)] public List Horaires { get; set; } } public class Horraire { [XmlElement(Horraire)] public string Horraire { get; set; } } XmlSerializer deserializer = new XmlSerializer(typeof(DestinatarieDestinatarie)); TextReader reader = new StreamReader(@D:\myXml.xml); object obj = deserializer.Deserialize(reader); Destinatarie XmlData = (Destinatarie)obj; reader.Close();

Valentin Martin · Answer

Ramesh can you try to help me with my code and variable??

Ramesh Maruthi · Answer

Hey Sorry Valentin Now I understood your problem you want do deserialize even the child nodes right ? can you give try in this way [Serializable()] [System.Xml.Serialization.XmlRootAttribute(Namespace =  IsNullable = false ElementName = rootnode)] public partial class RootNode { [System.Xml.Serialization.XmlElementAttribute(collection1)] public List OuterCollections { get; set; } } [Serializable()] public partial class OuterCollection { [XmlAttribute(attribute1)] public string attribute1 { get; set; } [XmlArray(ElementName = innercollection1)] [XmlArrayItem(text Type = typeof(InnerCollection1))] public List innerCollection1Stuff { get; set; } [XmlArray(innercollection2)] [XmlArrayItem(text typeof(InnerCollection2))] public List innerConnection2Stuff { get; set; } } [Serializable()] public partial class InnerCollection2 { [XmlText()] public string text { get; set; } } public partial class InnerCollection1 { [XmlText()] public int number { get; set; } }

Ramesh Maruthi · Answer

[System.Xml.Serialization.XmlElement( Technical Control )] public string Model { get; set; } Did u write this lines in car class ?

Valentin Martin · Answer

Hello For me If my XML is: 1020 Nissan Sentra 2007 2012 2014 >/Year> My program doesn't work. I don't arrive to deserialise the Technical Control level

Ramesh Maruthi · Answer

Hello Valentine Can you try it in this way [Serializable()] public class Car { [System.Xml.Serialization.XmlElement(StockNumber)] public string StockNumber { get; set; } [System.Xml.Serialization.XmlElement(Make)] public string Make { get; set; } [System.Xml.Serialization.XmlElement(Model)] public string Model { get; set; } } [Serializable()] [System.Xml.Serialization.XmlRoot(CarCollection)] public class CarCollection { [XmlArray(Cars)] [XmlArrayItem(Car typeof(Car))] public Car[] Car { get; set; } } The Deserialize function: CarCollection cars = null; string path = cars.xml; XmlSerializer serializer = new XmlSerializer(typeof(CarCollection)); StreamReader reader = new StreamReader(path); cars = (CarCollection)serializer.Deserialize(reader); reader.Close(); And the slightly tweaked xml (I needed to add a new element to wrap ...Net is picky about deserializing arrays): 1020 Nissan Sentra 1010 Toyota Corolla 1111 Honda Accord