How to add label in datagrid for windows form?

Question

Plz tell me how to add label in datagrid for windows form... plz help..!

Vasanth · Answer

Try this  private DataTable dtTemp = new DataTable (); private Label lbl = new Label (); DataGridTableStyle dgStyle = new DataGridTableStyle (); DataGridTextBoxColumn dgLabel = new DataGridTextBoxColumn (); private void Form1_Load( object sender System. EventArgs e) { //label property lbl.ForeColor = Color .Black; lbl.Font = new Font ( TimesRoman  12 FontStyle .Bold); dgStyle.GridColumnStyles.Add(dgLabel); dgLabel.HeaderText = Name ; dgLabel.MappingName = Name ; dgLabel.Width = 200; dgStyle.PreferredRowHeight = 24; dg .TableStyles.Add(dgStyle); //Create temp datatable for bind values DataTable dtTemp = new DataTable (); DataRow dr; //create schema dtTemp.Columns.Add( Name ); dtTemp.Columns.Add( City ); dtTemp.Columns.Add( State ); //Add temp datas dr = dtTemp.NewRow(); dr[ Name ] = AAA ; dr[ City ] = CAAA ; dr[ State ] = SAAA ; dtTemp.Rows.Add(dr); dr = dtTemp.NewRow(); dr[ Name ] = BBB ; dr[ City ] = CBBB ; dr[ State ] = SBBB ; dtTemp.Rows.Add(dr); dr = dtTemp.NewRow(); dr[ Name ] = CCC ; dr[ City ] = CCCC ; dr[ State ] = SCCC ; dtTemp.Rows.Add(dr); dr = dtTemp.NewRow(); dr[ Name ] = DDD ; dr[ City ] = CDDD ; dr[ State ] = SDDD ; dtTemp.Rows.Add(dr); dr = dtTemp.NewRow(); dr[ Name ] = EEE ; dr[ City ] = CEEE ; dr[ State ] = SEEE ; dtTemp.Rows.Add(dr); //Bind the datasourse dg .DataSource = dtTemp; } private void dg_MouseUp( object sender System.Windows.Forms. MouseEventArgs e) { if (dg.HitTest(e.X e.Y) != null ) { if (dg.HitTest(e.X e.Y).Column == 0) { dgLabel.TextBox.Controls.Add(lbl); lbl.Text = Hi Label  + dg[dg.CurrentRowIndex 0].ToString(); } } } Hope its help  please mark as answer.

Shailendra Verma · Answer

using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Text; using System.Windows.Forms; namespace DataGrid { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private DataTable dtTemp = new DataTable(); DataRow dr; private void Form1_Load(object sender EventArgs e) { // creating the object of Datagrid table style DataGridTableStyle dgStyle = new DataGridTableStyle(); // Creating the object of DataGridTextBoxColumn For Name DataGridTextBoxColumn dgLabel = new DataGridTextBoxColumn(); // Creating the object of DataGridTextBoxColumn For State DataGridTextBoxColumn dgLabel1 = new DataGridTextBoxColumn(); // Creating the object of DataGridTextBoxColumn for City DataGridTextBoxColumn dgLabel2 = new DataGridTextBoxColumn(); // Creating the object of DataGridTextBoxColumn For DateTime DataGridTextBoxColumn dgDateTime = new DataGridTextBoxColumn(); //Assigning the Header Text Name as Name And Mapping Name(Mapping Name is a Name which is in the table's column Name) dgLabel.HeaderText = Name; dgLabel.MappingName = Name; dgLabel.Width = 200; //Assigning the Header Text Name as State And Mapping Name(Mapping Name is a Name which is in the table's column Name) dgLabel1.HeaderText = State; dgLabel1.MappingName = State; dgLabel1.Width = 200; //Assigning the Header Text Name as City And Mapping Name(Mapping Name is a Name which is in the table's column Name) dgLabel2.HeaderText = City; dgLabel2.MappingName = City; dgLabel2.Width = 200; //Assigning the Header Text Name as DateTime And Mapping Name(Mapping Name is a Name which is in the table's column Name) dgDateTime.HeaderText = DateTime; dgDateTime.MappingName = DateTime; dgDateTime.Width=200; // Creating Schema For DataTable //Adding the column name with name as Name in DataTable dtTemp.Columns.Add(Name); //Adding the column name with name as State in DataTable dtTemp.Columns.Add(State); //Adding the column name with name as City in DataTable dtTemp.Columns.Add(City); //Adding the column name with name as DateTime in DataTable dtTemp.Columns.Add(DateTime); //Create the rows in DataTable dr = dtTemp.NewRow(); dr[Name] = Shailendra; dr[State] = U.P; dr[City] = Sultanpur; dr[DateTime] = 25/08/1988; dtTemp.Rows.Add(dr); // Binding The DataTable in DataGrid dataGrid1.DataSource = dtTemp; //Creating the object of Label and Setting the properties Label lbl = new Label(); lbl.Font = new Font(Verdana 8 FontStyle.Bold); lbl.Text = *; lbl.Left = 150; lbl.ForeColor = Color.Red; lbl.BackColor = Color.Green; //adding the Label control to dgLabel's TextBox dgLabel.TextBox.Controls.Add(lbl); //Creating the object of Label1 and Setting the properties Label lbl1 = new Label(); lbl1.Font = new Font(Verdana 8 FontStyle.Bold); lbl1.Left = 140; lbl1.Text = *; lbl1.ForeColor = Color.Red; lbl1.BackColor = Color.Green; //adding the Label control to dgLabel1's TextBox dgLabel1.TextBox.Controls.Add(lbl1); //Creating the object of Label2 and Setting the properties Label lbl2 = new Label(); lbl2.Font = new Font(Verdana 8 FontStyle.Bold); lbl2.Left = 140; lbl2.Text = *; lbl2.ForeColor = Color.Red; lbl2.BackColor = Color.Green; //adding the Label control to dgLabel's TextBox dgLabel2.TextBox.Controls.Add(lbl2); //Creating the object of DateTime and Setting the properties DateTimePicker dtp = new DateTimePicker(); dtp.CalendarForeColor = Color.Gold; //adding the DateTimePiker control to dgDateTime's TextBox dgDateTime.TextBox.Controls.Add(dtp); dgStyle.GridColumnStyles.Add(dgLabel); dgStyle.GridColumnStyles.Add(dgLabel1); dgStyle.GridColumnStyles.Add(dgLabel2); dgStyle.GridColumnStyles.Add(dgDateTime); dataGrid1.TableStyles.Add(dgStyle); dgStyle.PreferredRowHeight = 25; } } }

Anusha Srivastava · Answer

am not getting this- dataGridLable

Anusha Srivastava · Answer

Vasanth I am trying to make datagrid which have some readable feilds n some editable. Now i want to show user that the editable feilds are mandatory feilds so i want to use lable in each row Indicating * for each editable column. see i hv done this DataTable Item = new DataTable (); Item.Columns.Add( ItemCode  typeof ( string )); Item.Columns[ ItemCode ].ReadOnly = true ; Item.Columns.Add( ItemName  typeof ( string )); Item.Columns[ ItemName ].ReadOnly = true ; Item.Columns.Add( RecivedQuantity  typeof ( Int32 )); Item.Columns[ RecivedQuantity ].ReadOnly = true ; Item.Columns.Add( Approved  typeof ( Int32 )); Item.Columns.Add( Rejected  typeof ( Int32 )); Item.Rows.Add( I009  RAM  100 95 5); Item.Rows.Add( I002  Bolts  1025 1000 25); Item.Rows.Add( I004  MotherBoard  80 78 2); Item.Rows.Add( I005  ICs  125 100 25); //binding datagrid and assigning properties to it. dataGrid1.HeaderForeColor = Color .White; dataGrid1.HeaderBackColor = Color .Chocolate; dataGrid1.HeaderFont = new Font ( verdana  8 FontStyle .Bold); dataGrid1.CaptionText = Check Item ; dataGrid1.Width = 415; dataGrid1.DataSource = Item; now i hv tried to add lable bt not Succeeded. plz help.

Amit Choudhary · Answer

hi friend try this code: dataGridLable.TextBox.Controls.Add( lblControl ); lblControl.Text = dataGrid[dataGrid.CurrentRowIndex  0 ].ToString(); Please mark as answer if it helps