How to bind dynamically menus and submenus in silverlight 4

Question

Hi,

I need to good solution to bind Menus and its Sub Menus Dynamically in Silver Light4. I searched but cant find the exact one. Please help.

I got a List that contains Menus, Sub Menus. I need to Split it which is root Menu and its Sub Menus.

Thanks,
Vijay

Priya Linge · Answer

Hi Vijay, Generate Menu and SubMenu dynamically : //Namespace using System.Windows.Controls; using SL4PopupMenu; MainPage.Xaml private void GenerateMenu() { var data = new ObservableCollection ("Item 1,Item 2,Item 3,Item 4,Item 6".Split(',')); DataGrid dataGrid1 = new DataGrid() { ItemsSource = data,Height=700,Width=200 }; this.LayoutRoot.Children.Add(dataGrid1); // Create the submenu PopupMenu spmTimeNow = new PopupMenu(); spmTimeNow.AddItem("Time Now", null); // Create the main menu PopupMenu pm1 = new PopupMenu(); pm1.AddItem("Delete row", delegate { data.RemoveAt(pm1.GetClickedElement ().GetIndex()); }); pm1.AddSeparator(); pm1.AddSubMenu(spmTimeNow, "Get Time ", "Images/arrow.png", null, null, false, null); // Attach the submenu pmTimeSub pm1.AddSeparator(); //pm1.AddItem("Demo2", delegate { this.Content = new Demo2(); }); // Set dataGrid1 as the trigger element pm1.AddTrigger(TriggerTypes.RightClick, dataGrid1); // Showing main menu pm1.Showing += (sender, e) => { pm1.PopupMenuItem(0).Header = "Delete " + dataGrid1.SelectedItem; pm1.PopupMenuItem(0).IsVisible = pm1.PopupMenuItem(1).IsVisible = pm1.GetClickedElement () != null; }; // Showing submenu spmTimeNow.Showing += delegate { spmTimeNow.PopupMenuItem(0).Header = DateTime.Now.ToLongTimeString(); }; } public MainPage() { InitializeComponent(); GenerateMenu(); } Please check attached code file. Hope this will help you. Thanks.

How to bind dynamically menus and submenus in silverlight 4

Nilesh Shah