How to bind dynamically menus and submenus in silverlight 4

Question

Hi I need to good solution to bind Menus and its Sub Menus Dynamically in Silver Light4. I searched but cant find the exact one. Please help. I got a List that contains Menus Sub Menus. I need to Split it which is root Menu and its Sub Menus. Thanks Vijay

Priya Linge · Answer

Hi Vijay Generate Menu and SubMenu dynamically : //Namespace using System.Windows.Controls; using SL4PopupMenu; MainPage.Xaml private void GenerateMenu() { var data = new ObservableCollection (Item 1Item 2Item 3Item 4Item 6.Split('')); DataGrid dataGrid1 = new DataGrid() { ItemsSource = dataHeight=700Width=200 }; this.LayoutRoot.Children.Add(dataGrid1); // Create the submenu PopupMenu spmTimeNow = new PopupMenu(); spmTimeNow.AddItem(Time Now null); // Create the main menu PopupMenu pm1 = new PopupMenu(); pm1.AddItem(Delete row delegate { data.RemoveAt(pm1.GetClickedElement ().GetIndex()); }); pm1.AddSeparator(); pm1.AddSubMenu(spmTimeNow Get Time  Images/arrow.png null null false null); // Attach the submenu pmTimeSub pm1.AddSeparator(); //pm1.AddItem(Demo2 delegate { this.Content = new Demo2(); }); // Set dataGrid1 as the trigger element pm1.AddTrigger(TriggerTypes.RightClick dataGrid1); // Showing main menu pm1.Showing += (sender e) => { pm1.PopupMenuItem(0).Header = Delete  + dataGrid1.SelectedItem; pm1.PopupMenuItem(0).IsVisible = pm1.PopupMenuItem(1).IsVisible = pm1.GetClickedElement () != null; }; // Showing submenu spmTimeNow.Showing += delegate { spmTimeNow.PopupMenuItem(0).Header = DateTime.Now.ToLongTimeString(); }; } public MainPage() { InitializeComponent(); GenerateMenu(); } Please check attached code file. Hope this will help you. Thanks.