How to convert ReadOnlyCollection class data to xml data

Question

I have class as ReadOnlyCollection dataSalesReceipt ; dataSalesReceipt = new ReadOnlyCollection (customerQueryService.ExecuteIdsQuery(select * from SalesReceipt).ToList()); How can i convert dataSalesReceipt collection into xml data.? dataSalesReceipt contains container subtag of data. Ex: BillAddress is main container(Property) which have City  Street are sub tags.

Mrudul Ganpule · Answer

Thank you for your valuable reply  i'll try this solution in my project ..

Umesh Kumar · Answer

Hi Can you try this too public static string Serialize ( object dataToSerialize ) { if ( dataToSerialize == null ) return null ; using ( StringWriter stringwriter = new System . IO . StringWriter ()) { var serializer = new XmlSerializer ( dataToSerialize . GetType ()); serializer . Serialize ( stringwriter  dataToSerialize ); return stringwriter . ToString (); } } public static T Deserialize T >( string xmlText ) { if ( String . IsNullOrWhiteSpace ( xmlText )) return default ( T ); using ( StringReader stringReader = new System . IO . StringReader ( xmlText )) { var serializer = new XmlSerializer ( typeof ( T )); return ( T ) serializer . Deserialize ( stringReader ); } }

Umesh Kumar · Answer

Hi Good day Suppose I have a collection List Employee > empList = new List Employee >(); empList.Add( new Employee () { ID = 1 FName = John  LName = Shields  DOB = DateTime .Parse( 12/11/1971 ) Sex = 'M' }); empList.Add( new Employee () { ID = 2 FName = Mary  LName = Jacobs  DOB = DateTime .Parse( 01/17/1961 ) Sex = 'F' }); empList.Add( new Employee () { ID = 3 FName = Amber  LName = Agar  DOB = DateTime .Parse( 12/23/1971 ) Sex = 'M' }); empList.Add( new Employee () { ID = 4 FName = Kathy  LName = Berry  DOB = DateTime .Parse( 11/15/1976 ) Sex = 'F' }); empList.Add( new Employee () { ID = 5 FName = Lena  LName = Bilton  DOB = DateTime .Parse( 05/11/1978 ) Sex = 'F' }); empList.Add( new Employee () { ID = 6 FName = Susanne  LName = Buck  DOB = DateTime .Parse( 03/7/1965 ) Sex = 'F' }); empList.Add( new Employee () { ID = 7 FName = Jim  LName = Brown  DOB = DateTime .Parse( 09/11/1972 ) Sex = 'M' }); empList.Add( new Employee () { ID = 8 FName = Jane  LName = Hooks  DOB = DateTime .Parse( 12/11/1972 ) Sex = 'F' }); empList.Add( new Employee () { ID = 9 FName = Robert  LName =   DOB = DateTime .Parse( 06/28/1964 ) Sex = 'M' }); empList.Add( new Employee () { ID = 10 FName = Cindy  LName = Fox  DOB = DateTime .Parse( 01/11/1978 ) Sex = 'M' }); Code to convert to xml var xEle = new XElement ( Employees  from emp in empList select new XElement ( Employee  new XAttribute ( ID  emp.ID) new XElement ( FName  emp.FName) new XElement ( LName  emp.LName) new XElement ( DOB  emp.DOB) new XElement ( Sex  emp.Sex) ));