how to create Id column data as link button in mvc5 razor

Question

hi frnds

i have a web grid with column name like ID ,Name ,Address

in this id column i gave id like 101 , 202 etc
now i want these id like 101 ,202 open like link button so in that if i click on 101 so another grid view should be open so how to do this mean
how to give every data as a link button on a Id column

Vaibhav Deshmukh · Answer

Hi Anjali, You want ID column data to be display to the user and its clickable(Link Button) so just follow below steps, In View -The following view is List (Scaffolding of type List as view) table class = "table" > thead > tr > th > Id Column > > > tbody > @foreach (var item in Model) { tr id = "mytable" > td > a href = "~/UserList/GetData/@item.RegisterId" class = "btn btn-default" > @item.RegisterId > > > } > > In my case link is ~/UserList/GetData/@item.RegisterId Hope this will help you, Accept the answer if you get what you are looking for.

Amit Kumar · Answer

Hi Dear, For each row am I right ? U want to add multiple buttons and you want to know that which button I clicked . For this problem you can generate button dynamic and create its ids follow the below link. https://mrsarker.wordpress.com/2012/11/13/reusable-asp-net-mvc-user-control-in-angularjs-same-page/ http://www.ezzylearning.com/tutorial/using-button-columns-in-gridview http://www.aspsnippets.com/Articles/ASPNet-GridView---Get-CommandName-and-CommandArgument-of-Button-clicked-in-RowCommand-and-Click-events.aspx

Anjali Khan · Answer

my qus is i have a reg form so i filled all details and saveed to data base now these data is showing gridview .i want i gave id so how to generate this id column data as click event

Anjali Khan · Answer

now I did not gave any css .simply created view with model and my code is div > @Html.ActionLink( "Home" , "Index" , "Home" ) div > div style =" width : 80% ; height : 80% ; text-align : center"> div > @Html.LabelFor(model => model.Company) @Html.EditorFor(model => model.Company) @Html.ValidationMessageFor(model => model.Company) div >

Amit Kumar · Answer

Hi Dear, Please follow the below link.. http://stackoverflow.com/questions/12318905/mvc-razor-button-click-even-pass-parameter-with-it http://stackoverflow.com/questions/31954101/webgrid-mvc-5-show-action-buttons-based-on-authentication-and-authorization

Naveen Bisht · Answer

hiddenDiv.Column("",style: "col1",format: @ @Html.ActionLink("ControllerName","ActionName",null, new { @class="yourCssClass", @onclick="YourOnClickMethodName(this)"}) )

how to create Id column data as link button in mvc5 razor

Ravi Kumar