how to display only the textbox record in the datagridview in the same form c#

Question

like that;

i have one form.
inside the form have 4 textbox, one datagridview and one save button.

when, i enter the record into the textbox and then press the save button, the datagridview show me the current record (not all the records in the table)when, i enter the textbox record.

Satyapriya Nayak · Answer

Form1.cs using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.Data.OleDb; namespace Insert_Update_Delete_DataGridView { public partial class Form1 : Form { string ConnectionString = System.Configuration.ConfigurationSettings.AppSettings[dsn]; OleDbCommand com; OleDbDataAdapter oledbda; string str; DataSet ds; public Form1() { InitializeComponent(); } private void Form1_Load(object sender EventArgs e) { bindgrid(); } private void bindgrid() { OleDbConnection con = new OleDbConnection(ConnectionString); con.Open(); str = select * from employee; com = new OleDbCommand(str con); oledbda = new OleDbDataAdapter(com); ds = new DataSet(); oledbda.Fill(ds employee); dataGridView1.DataMember=employee; dataGridView1.DataSource = ds; con.Close(); } private void Clear() { txt_sno.Text = ; txt_name.Text = ; txt_address.Text = ; txt_age.Text = ; } private void btn_edit_Click(object sender EventArgs e) { int i; i = dataGridView1.SelectedCells[0].RowIndex; txt_sno.Text = dataGridView1.Rows[i].Cells[1].Value.ToString(); txt_name.Text = dataGridView1.Rows[i].Cells[2].Value.ToString(); txt_address.Text = dataGridView1.Rows[i].Cells[3].Value.ToString(); txt_age.Text = dataGridView1.Rows[i].Cells[4].Value.ToString(); } private void btn_update_Click(object sender EventArgs e) { OleDbConnection con = new OleDbConnection(ConnectionString); con.Open(); str = Update employee set sno=@snoname=@nameaddress=@addressage=@age Where sno=@sno; com = new OleDbCommand(str con); com.Parameters.AddWithValue(@sno txt_sno.Text); com.Parameters.AddWithValue(@name txt_name.Text); com.Parameters.AddWithValue(@address txt_address.Text); com.Parameters.AddWithValue(@age txt_age.Text); com.ExecuteNonQuery(); MessageBox.Show(Record Successfully Updated); con.Close(); bindgrid(); Clear(); } private void btn_delete_Click(object sender EventArgs e) { OleDbConnection con = new OleDbConnection(ConnectionString); com = new OleDbCommand(); if (dataGridView1.Rows.Count > 1 && dataGridView1.SelectedRows[0].Index != dataGridView1.Rows.Count - 1) { com.CommandText = DELETE FROM employee WHERE ID= + dataGridView1.SelectedRows[0].Cells[0].Value.ToString() + ; con.Open(); com.Connection = con; com.ExecuteNonQuery(); con.Close(); dataGridView1.Rows.RemoveAt(dataGridView1.SelectedRows[0].Index); MessageBox.Show(Record Successfully Deleted); } bindgrid(); } private void btn_insert_Click(object sender EventArgs e) { OleDbConnection con = new OleDbConnection(ConnectionString); con.Open(); str = Insert into employee(snonameaddressage) Values (@sno@name@address@age); com = new OleDbCommand(str con); com.Parameters.AddWithValue(@sno txt_sno.Text); com.Parameters.AddWithValue(@name txt_name.Text); com.Parameters.AddWithValue(@address txt_address.Text); com.Parameters.AddWithValue(@age txt_age.Text); com.ExecuteNonQuery(); con.Close(); MessageBox.Show(Record Successfully Inserted); bindgrid(); Clear(); } } }