how to enable button click on any node in treeview in asp.n

Question

Hi frnds

how to enable button click on any node in treeview in asp.net ?

when i click on tree view any node then my submit button should be enable how to do this . i am sending my button and javascript code

<asp:Button ID="btnSubmit" style="display:none" runat="server" Text="Send" CssClass="btn btn-primary"/>

<asp:TreeView ID="TreeView1" runat="server" ShowCheckBoxes="All" onclick="forClicked(this)" Checked="false"></asp:TreeView>

<script lang="javascript" type="text/javascript">

$(function () {

$("[id*=TreeView1] input[type=checkbox]").bind("click", function () {

var table = $(this).closest("table");

if (table.next().length > 0 && table.next()[0].tagName == "DIV") {

//Is Parent CheckBox

// var childDiv = table.next();

var isChecked = $(this).is(":checked");

$("input[type=checkbox]", childDiv).each(function () {

if (isChecked) {

$(this).attr("checked", "checked");

} else {

$(this).removeAttr("checked");

}

});

} else {

//Is Child CheckBox

// var parentDIV = $(this).closest("DIV");

if ($("input[type=checkbox]", parentDIV).length == $("input[type=checkbox]:checked", parentDIV).length) {

$("input[type=checkbox]", parentDIV.prev()).attr("checked", "checked");

} else {

$("input[type=checkbox]", parentDIV.prev()).removeAttr("checked");

}

}

});

})

</script>

Answer 1

hi,

As per me, this error occurs when you trying to access null object's properties / methods / public attribute or converting null object into other type of object.

here i think DataGridView1.CurrentRow.Cells["Column1"].Value has null value and your are trying to call is Tostring Method.

try...

data.slno = Convert.Tostring(DataGridView1.CurrentRow.Cells["Column1"].Value);

hope this will help you.

Answer 2

i have library file there i intialised database add parameters
now from application file i hv to update database

Answer 3

Hi,
        
Before assigning the value to your class object, can you display the value like this

var temp=DataGridView1.CurrentRow.Cells["Column1"].Value;

MessageBox.Show(temp);
        
Regards,
Iftikar