How to generate bill numbers dynamically....

Question

sir. please give about How to generate bill numbers dynamically...

Priya Linge · Answer

Hi Random randnum = new Random(); 1.int num = randnum.Next(); 2.int num = random.Next(100); It generate a positive number up to 100 including 0. 3.int num = random.Next(1 100); It generates a number between 1 and 100. For more information check below link. http://www.c-sharpcorner.com/UploadFile/mahesh/RandomNumber11232005010428AM/RandomNumber.aspx Hope this will help you. Thanks.

vel kumar · Answer

You can use Random class for generating number like below private int RandomNumber(int min int max) { Random random = new Random(); return random.Next(min max); }