How to open a model window on click on any row of datagrid?

Question

Hi i want to open a model window on click on datagrid. Can it be possible??

Niradhip Chakraborty · Answer

Say your datagrid id is : dgrdExhibitorInfo public void dgrdExhibitorInfo_ItemDataBound(object sender, System.Web.UI.WebControls.DataGridItemEventArgs e) { if (e.Item.ItemType == ListItemType.AlternatingItem || e.Item.ItemType == ListItemType.Item) { e.Item.Attributes.Add("onclick", "OpenWin(this)"); } } function OpenWin(obj) { strUrl="xyz.aspx"; x = window.showModalDialog(strUrl,"newwin","dialogHeight:40;dialogWidth:60; status:No; edge:Raised; center:yes; help:No; resizable:No; ") }

Milton Smith · Answer

Thanks Niradhip

Niradhip Chakraborty · Answer

Milton Smith · Answer

It's working fine.How to show a hand sign onmouseover of datagrid?

Milton Smith · Answer

Hi Niradhip can you please send me the code.I am confused.

Niradhip Chakraborty · Answer

You can use the datagrid item databound event to accomplish this tusk. Inside item databound event you can call the java script function to open the page.

How to open a model window on click on any row of datagrid?

Answers (6)