How to print a unique elements of an Array?

Question

Anil Jha · Answer

I have seen many answeres here but all the answers are in old style but C# has grown now. By using LINQ you can achieve it in a minimal code. Try to find unique elements in array using below simple approach. class Program { static void Main( string [] args) { int [] items = { 2 5 7 5 8 10 8 }; IEnumerable int > uniqueItems = items.Distinct int >(); Console.WriteLine( Unique array items:  + string .Join(   uniqueItems)); Console.ReadLine(); } } /* Output: Unique array items: 2 5 7 8 10 */

Rajkiran Swain · Answer

/* * C program to print all unique elements of an unsorted array */ #include #include int main() { int array[100] size i j; printf( Enter number of elements in array
 ); scanf( %d  &size); printf( Enter %d numbers
  size); for (i = 0; i scanf( %d  &array[i]); } printf( Unique Elements
 ); for (i = 0; i for (j=0; j if (array[i] == array[j]) break ; } if (i == j){ /* No duplicate element found between index 0 to i */ printf( %d   array[i]); } } getch(); return 0; }

Manikandan Murugesan · Answer

Refer the below code to print unique elements in array: using System; public class Exercise6 { public static void Main() { int nctr=0; int [] arr1 = new int [100]; int i j k; Console.Write(

Print all unique elements of an array:
 ); Console.Write( ------------------------------------------
 ); Console.Write( Input the number of elements to be stored in the array : ); n = Convert.ToInt32(Console.ReadLine()); Console.Write( Input {0} elements in the array :
 n); for (i=0;i { Console.Write( element - {0} :  i); arr1[i] = Convert.ToInt32(Console.ReadLine()); } /*Checking duplicate elements in the array */ Console.Write( 
The unique elements found in the array are : 
 ); for (i=0; i { ctr=0; /*Check duplicate bifore the current position and increase counter by 1 if found.*/ for (j=0; j { /*Increment the counter when the seaarch value is duplicate.*/ if (arr1[i]==arr1[j]) { ctr++; } } /*Check duplicate after the current position and increase counter by 1 if found.*/ for (k=i+1; k { /*Increment the counter when the seaarch value is duplicate.*/ if (arr1[i]==arr1[k]) { ctr++; } } /*Print the value of the current position of the array as unique value when counter remain contains its initial value.*/ if (ctr==0) { Console.Write( {0}  arr1[i]); } } Console.Write(

); } }

Naveen A · Answer

can you explain with C# Program using foreach statement to print an unique array.Thank You...

Sundar · Answer

#include #include using namespace std; void printDistinct(int arr[] int n) { // Pick all elements one by one for (int i=0; i { // Check if the picked element is already printed int j; for (j=0; j if (arr[i] == arr[j]) break; // If not printed earlier then print it if (i == j) cout } } // Driver program to test above function int main() { int arr[] = {6 10 5 4 9 120 4 6 10}; int n = sizeof(arr)/sizeof(arr[0]); printDistinct(arr n); return 0; } Run on IDE