how to return textbox value after saving ,next time display

Question

sir, how can i display textbox value after saving and next time to open the form that time display these value .so please to help for codeing.

Sanjay Kumar · Answer

Hi protected void Button1_Click(object sender, EventArgs e) { Insert(); } public void Insert() { try { _conn = new SqlConnection(con); _cmd = new SqlCommand(); _cmd.Connection = _conn; _conn.Open(); _cmd.CommandType = CommandType.StoredProcedure; _cmd.CommandText = "insert_date"; _cmd.Parameters.Add("@Date",SqlDbType.DateTime).Value = DateTime.Now; _cmd.ExecuteNonQuery(); _conn.Close(); } catch (Exception ex) { } } http://www.w3schools.com/sql/func_getdate.asp

Sanjay Kumar · Answer

Hi protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { TextBox1.Text = DateTime.Now.ToString(); //or TextBox2.Text = System.DateTime.Now.Date.ToString("dd/MM/yyyy"); } }

Mohan kadam · Answer

sir , i am saving my account setting information then next time to open these form that time to display same data previous saving. so help me.

Sanjay Kumar · Answer

Hi Please give us some more details.

how to return textbox value after saving ,next time display

Answers (4)