List View

Question

My problem.
This is code.

            listView1.Columns.Add("Col1");
            listView1.Columns.Add("Col2");

            string[] strArrGroups = new string[3] { "FIRST", "SECOND", "THIRD" };
            string[] strArrItems = new string[4] { "one", "two", "tri", "cetiri" };
            for (int i = 0; i < strArrGroups.Length; i++)
            {
                int groupIndex = listView1.Groups.Add(new ListViewGroup(strArrGroups[i], HorizontalAlignment.Left));
                for (int j = 0; j < strArrItems.Length; j++)
                {
                    ListViewItem lvi = new ListViewItem(strArrItems[j]);
                    lvi.SubItems.Add("Hasta la Vista, Mon Cherri!");
                    listView1.Items.Add(lvi);
                    listView1.Groups[i].Items.Add(lvi);
                }
            }

I dont now how to include new column and write in new column
new srting[] strArrPrimer = {"1","2","3","4"}

Thanks for help

sasa lazic · Answer

I solve problem this is code //listView1.View = View.Details; //listView1.GridLines = true; //listView1.FullRowSelect = false; ////Add column header //listView1.Columns.Add(XXXXXXXXX 70); //listView1.Columns.Add(YYYYYYYY 70); //listView1.Columns.Add(ZZZZZZZZZ 70); //listView1.Columns.Add(DDDDDDDD 70); ////Add items in the listview //string[] arr = new string[4]; //ListViewItem itm; ////Add first item //arr[0] = product_1; //arr[1] = 100; //arr[2] = 10; //arr[3] = to care; //itm = new ListViewItem(arr); //listView1.Items.Add(itm); ////listView1.Items[0].Group = listView1.Groups[0]; //listView1.Groups[0].Items.Add(itm); ////Add second item //arr[0] = product_2; //arr[1] = 200; //arr[2] = 20; //arr[3] = to care; //itm = new ListViewItem(arr); //listView1.Items.Add(itm); ////listView1.Items[1].Group = listView1.Groups[1]; //listView1.Groups[1].Items.Add(itm); just add group in ListView Tasks Thats all

sasa lazic · Answer

I am not solve jet what i want again I want make listView with group this is my code string[] strArrGroups = new string[3] { ZERO SECOND THIRD }; int groupIndex = listView1.Groups.Add(new ListViewGroup(strArrGroups[0] HorizontalAlignment.Left)); listView1.View = View.Details; listView1.GridLines = true; listView1.FullRowSelect = false; //Add column header listView1.Columns.Add(XXXXXXXXX 70); listView1.Columns.Add(YYYYYYYY 70); listView1.Columns.Add(ZZZZZZZZZ 70); listView1.Columns.Add(DDDDDDDD 70); //Add items in the listview string[] arr = new string[4]; ListViewItem itm; //Add first item arr[0] = product_1; arr[1] = 100; arr[2] = 10; arr[3] = to care; itm = new ListViewItem(arr); listView1.Items.Add(itm); //listView1.Items[0].Group = listView1.Groups[0]; listView1.Groups[0].Items.Add(itm); //Add second item arr[0] = product_2; arr[1] = 200; arr[2] = 20; arr[3] = to care; itm = new ListViewItem(arr); listView1.Items.Add(itm); //listView1.Items[1].Group = listView1.Groups[1]; listView1.Groups[1].Items.Add(itm); when i run listview show me frst group default???? but in a second gropu show group ZERO. I want frst gropu ZERO input in columns arr[0] to arr[3] (produst110010to care) after that new gropu SECON and in this group i want to see arr[0] to arr[3] (produst220020to care) thanks

Upamanyu Roy Choudhury · Answer

A table is a combination of rows and columns so if you have to insert 1234 in column 3 then you have to first select the rows where you want to insert it. In a particular group say in group 3 traverse with the for loop  select the items and replace it with 1234 or you can create a new group and insert it. Try it in your own and keep me posted.

sasa lazic · Answer

I want to look like this. See Image. And i want in clo3 insert new srting[] strArrPrimer = {1234} thanks again Example: col1 col2 col3 frst-------------------- bla bla blA bla bla blA bla bla blA bla bla blA SECOND---------------- bla bla blA bla bla blA bla bla blA bla bla blA THIRD---------------- bla bla blA bla bla blA bla bla blA bla bla blA FOURT---------------- bla bla blA bla bla blA bla bla blA bla bla blA FIVE---------------- bla bla blA bla bla blA bla bla blA bla bla blA

Upamanyu Roy Choudhury · Answer

A new Group Group3 is created and a new Column .. NewColumn is added with values 123 and 4 and displayed like the earlier ones FOUR ------------------------------------------------- 1 2 3 4

Upamanyu Roy Choudhury · Answer

This new column will be added jujst like previuos 3 and 1234 will be added into it. How do you want them to look like??

sasa lazic · Answer

Its work and thanks for fast replay. But must be one but. Maybe i dont explain correctly what i wont. i nedd new column thets ok. and i want write string 1234 in new column now new srting[] strArrPrimer = {1234} write like new group thanks again

Upamanyu Roy Choudhury · Answer

Hi Sasa We can do it in many ways but I did it the way you wrote it. listView1.Columns.Add(Col1); listView1.Columns.Add(Col2); string[] strArrGroups = new string[3] { FIRST SECOND THIRD }; string[] strArrItems = new string[4] { one two tri cetiri }; for (int i = 0; i { int groupIndex = listView1.Groups.Add(new ListViewGroup(strArrGroups[i] HorizontalAlignment.Left)); for (int j = 0; j { ListViewItem lvi = new ListViewItem(strArrItems[j]); lvi.SubItems.Add(Hasta la Vista Mon Cherri!); listView1.Items.Add(lvi); listView1.Groups[i].Items.Add(lvi); } } //Newly added code for the new column listView1.Columns.Add(NewColumn); listView1.Groups.Add(new ListViewGroup(FOURTH HorizontalAlignment.Left)); string[] strArrPrimer= new string[] {1234}; for (int j = 0; j { ListViewItem lv = new ListViewItem(strArrPrimer[j]); listView1.Items.Add(lv); listView1.Groups[3].Items.Add(lv); } If you run it you will see the output and column4 is bening added to the list. If you find this post as useful please mark it as an answer