Method overloading in C#

Question

Hi How can we overload a method in C#?

Jignesh Trivedi · Answer

Hi C# allows us to define multiple functions with the same name differing in the number type and order of arguments. This is termed as function overloading. static void ShowMyValue() { ShowMyValue(No Value Define.); } static void ShowMyValue(string value) { Console.WriteLine(value); } hope this will help you.

Satyapriya Nayak · Answer

Hi Aman In Vb.net Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-qformat:yes;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin:0in;mso-para-margin-bottom:.0001pt;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibrisans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-fareast-font-family:Times New Roman;mso-fareast-theme-font:minor-fareast;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;} Overloading : - It is a process of using several procedures with the same name but having different signatures. The signature changes in number of parameters type of parameter and order of parameter. Program Public Class Form1 Private Sub Button1_Click( ByVal sender As System.Object ByVal e As System.EventArgs) Handles Button1.Click raj() raj(2) raj(3 3) raj( ravi  1) raj(100 rahul ) End Sub Public Overloads Sub raj() MsgBox( Hello Raj ) End Sub Public Overloads Sub raj( ByVal x As Integer ) MsgBox(x * 5) End Sub Public Overloads Sub raj( ByVal x As Integer  ByVal y As Integer ) MsgBox(x + y) End Sub Public Overloads Sub raj( ByVal s As String  ByVal x As Integer ) MsgBox(s & :has achieved rank & x) End Sub Public Overloads Sub raj( ByVal x As Integer  ByVal s As String ) MsgBox(s & :has secured & x) End Sub End Class Thanks

Nattudurai Eswaramurthy · Answer

Its very simple... same method name for different Methods but it differs by Parameters... public int Add() { return 10; } public int Add(int a int b) { return a+b; } public float Add(float a float b) { return a+b; }

Santhosh Kumar Jayaraman · Answer

Check this. http://www.codeproject.com/Articles/17951/Function-Overloading

Vulpes · Answer

By giving it a different number and/or type(s) of parameters. For example: public void MyMethod() { // code } public void MyMethod(int i) { // code } public string MyMethod(int i string s) { // code } shows 3 overloads of MyMethod. Notice that the return type of a method plays no part in overload resolution and so needn't be the same for every overload.