Most repeating number in sequence and its starting position

Question

Suppose I have an array of integer arr[1,2,3,1,1,1,2,2,3,3] .Here 1 is most repeated from position arr[3] to arr[5] for 3 times. Ho to find its starting position i.e arr[3] and total repeated count i.e 3 programmatically.

Dharmraj Thakur · Answer

You can do this... static void Main( string [] args) { int [] data = { 1, 2, 3, 1, 1, 1, 2, 2, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4 }; var result = data.GroupBy(a => a) .Select(a => new { Number = a.FirstOrDefault(), Count = a.Count() }) .OrderByDescending(a => a.Count).FirstOrDefault(); Console.WriteLine( "Most repeting number : " + result.Number); Console.WriteLine( "Element Index : " + data.ToList().IndexOf(result.Number)); Console.ReadKey(); }

Altaf Ansari · Answer

Please Try: int [] arr = new int [] { 1, 2, 3, 1, 1, 1, 2, 2, 3, 3 }; // group by value and count frequency var query = from i in arr.ToList().Skip(3).Take(5).ToList() group i by i into g select new { g.Key, Count = g.Count() }; // compute the maximum frequency int repeated_count = query.Max(g => g.Count); // find the values with that frequency IEnumerable int > modes = query .Where(g => g.Count == repeated_count) .Select(g => g.Key); // Find Positon to console foreach (var mode in modes) { int position = arr.ToList().IndexOf(mode); }

Amrit Thapaliya · Answer

Console.WriteLine("Count: " + (result.Count)); To get the count. Thanks Dharmraj Thakur

Most repeating number in sequence and its starting position

Answers (3)