MVC

Question

How to implement Next button in Edit view If i click Next button it should fetch next record and should display in same view and in same fields please help me in code Thank you

abhi lash · Answer

Edit View @model StudentNext.Models.Student @{ ViewBag.Title = Edit; } Edit @using (Html.BeginForm()) { @Html.AntiForgeryToken() Student @Html.ValidationSummary(true  new { @class = text-danger }) @Html.HiddenFor(model => model.SID) @Html.LabelFor(model => model.SID htmlAttributes: new { @class = control-label col-md-2 }) @Html.EditorFor(model => model.SID new { htmlAttributes = new { @class = form-control@id=sid } }) @Html.ValidationMessageFor(model => model.SID  new { @class = text-danger }) @Html.LabelFor(model => model.StudentName htmlAttributes: new { @class = control-label col-md-2 }) @Html.EditorFor(model => model.StudentName new { htmlAttributes = new { @class = form-control@id = sname } }) @Html.ValidationMessageFor(model => model.StudentName  new { @class = text-danger }) @Html.LabelFor(model => model.Father_Name htmlAttributes: new { @class = control-label col-md-2 }) @Html.EditorFor(model => model.Father_Name new { htmlAttributes = new { @class = form-control @id = fname } }) @Html.ValidationMessageFor(model => model.Father_Name  new { @class = text-danger }) @Html.LabelFor(model => model.MotherName htmlAttributes: new { @class = control-label col-md-2 }) @Html.EditorFor(model => model.MotherName new { htmlAttributes = new { @class = form-control @id = mname } }) @Html.ValidationMessageFor(model => model.MotherName  new { @class = text-danger }) @Html.LabelFor(model => model.Address htmlAttributes: new { @class = control-label col-md-2 }) @Html.EditorFor(model => model.Address new { htmlAttributes = new { @class = form-control @id = add } }) @Html.ValidationMessageFor(model => model.Address  new { @class = text-danger }) @Html.LabelFor(model => model.PhoneNumber htmlAttributes: new { @class = control-label col-md-2 }) @Html.EditorFor(model => model.PhoneNumber new { htmlAttributes = new { @class = form-control @id = pno } }) @Html.ValidationMessageFor(model => model.PhoneNumber  new { @class = text-danger }) } @Html.ActionLink(Back to List Index) $(#nextbtn).click(function () { var stdnextid = $(#sid).val() + 1; $.getJSON('/Home/getnextrecord?id=' + stdnextid function (result) { $(#sid ).val(result.id); $(#sname ).val(result.name); $(#fname ).val(result.name); $(#mname ).val(result.name); $(#add ).val(result.name); $(#pno ).val(result.name); }); }); My Edit Controler // GET: Students/Edit/5 public ActionResult Edit(int? id) { if (id == null) { return new HttpStatusCodeResult(HttpStatusCode.BadRequest); } Student student = db.Students.Find(id); if (student == null) { return HttpNotFound(); } return View(student); } // POST: Students/Edit/5 // To protect from overposting attacks please enable the specific properties you want to bind to for // more details see http://go.microsoft.com/fwlink/?LinkId=317598. [HttpPost] [ValidateAntiForgeryToken] public ActionResult Edit([Bind(Include = SIDStudentNameFather_NameMotherNameAddressPhoneNumber)] Student student) { if (ModelState.IsValid) { db.Entry(student).State = EntityState.Modified; db.SaveChanges(); return RedirectToAction(Index); } return View(student); }

Suraj Sahoo · Answer

Hi Abhi It is not possible on my part to anticipate what your need is. Please share your code what you want then I can write up. Thanks

abhi lash · Answer

Please send me the code Suraj

Suraj Sahoo · Answer

Ok Abhi got you here In that case you can do the following to acheive the same: 1- On click of the next button make an ajax call to retrieve the records from database that you want to show and on the success of ajax manipulate the View i.e. if you are showing the records in a table tr td then manipulate the td tr with the new set of records you want to show to the user. Thus you can achieve this using ajax asynchronous call and making request to HttpGet action method. I hope you got me here. Thanks Accept if this helps you anyway.

abhi lash · Answer

@Suraj i dont want grid view...i have edit view in that i have save button in that same view i want next button if i click next button it should fetch the record from database and should display it in same view and if i click save button it should save

Suraj Sahoo · Answer

Hello Abhi I think your requirement is to show Records in a grid view. Please follow the below links to implement Grid.MVC in MVC application. it is simple and easy. http://www.codeproject.com/Tips/597253/Using-the-Grid-MVC-in-ASP-NET-MVC http://surajpassion.in/a-simple-way-to-implement-grid-using-mvc/ I hope this helps. Thanks