Newbie need help understanding multi parameter lambda?

Question

Hi I'm new to coding and C# in general but I do know basics of the program. I also like LINQ but recently I came across a piece of code in the internet (on a website) var matchCount = deqn.Value.Select((c i) => deqn.Value.Substring(i)).Count(sub => sub.StartsWith( 	ag )); where deqn is a xml node and the above code is to find how many times the string 	ag appears in that node. I can't figure out how the code works....I'm not familiar with multi parameter lambda expressions. Can anyone explain (break it down) the code in details to me?

Mukesh Nayak · Answer

Hi Laxman  Now there is 2 extension for the select . Please refer the image below : First extension in the image above is having one parameter which is just element itself to be manipulated. Now in the second case it is accepting 2 parameter where the first parameter is the element itself and second parameter is the index. Now in you code using second parameter you are iterating through the all the value using substring. For example if your deqn.value = \tag SIGMA INSTITUTE so it will iterate and get all the value such as \tagSIGMA INSTITUTE (i = 0) tagSIGMA INSTITUTE (i=1) agSigMA INSTITUTE (i = 3) .. .. E (i = n) then from all this element its checking where there \tag and getting count. Regards Mukesh Nayak

Laxmidhar Sahoo · Answer

hi mukesh The first is the iterated charecter second is the position(index) of the iterated charecter

Laxmidhar Sahoo · Answer

sir I made some changes with your code and bellow given a example .sir I look it and get back to me public ActionResult testdoublelambdacount() { string strxml =   +   +  \tag SIGMA INSTITUTE  +  650  +  +   +  ORCHID INSTITUTE  +  1200  +  +  ; XmlDocument xDoc = new XmlDocument(); xDoc.LoadXml(strxml); XmlNodeList xmlNodeList = xDoc.SelectNodes( /info/collage ); foreach (XmlNode xmlNode in xmlNodeList) { string nodevalue = xmlNode[ name ].InnerText; var matchCount = nodevalue.Select((c i) => nodevalue.Substring(i)).Count(sub => sub.StartsWith( \tag )); } return View(); }

Mukesh Nayak · Answer

Hi Laxman I modified the code something like var matchCount = deqn.Select((c i) => deqn.Substring(i) +  Iteration :  + i +  Element :  + c ).ToList(); and putting the break point you will get the following : So i = 0 deqn.Substring(i) = \tagSIGMA INSTITUTE c = i = 1 deqn.Substring(i) = \tagSIGMA INSTITUTE c =\ i = 2  deqn.Substring(i) = tagSIGMA INSTITUTE c =t ......... ......... Mukesh Nayak

Ab Laxman · Answer

Hi Mukesh Are the below strings values of  c  in the lambda? \tagSIGMA INSTITUTE (i = 0) tagSIGMA INSTITUTE (i=1) agSigMA INSTITUTE (i = 3) or are they the value of  i ? Sorry if this question sounds stupid but I'm a newby:)