open the new form with in the another form button click event

Question

hai i have 2 forms names are form1form2 with in the form1 in button click event i want open the new form that is form2 and form 2 is close. for this i write button1_click( object sendereventargs e) { form2 f2=new form2(); form2.show(); this.close(); } but here 2 forms will close that is the problem dont suggest hide() method if you know any other way to open form2 tell to me.......

Dipa Ahuja · Answer

hi.. you can do this way.. form1 button click: private void button1_Click(object sender EventArgs e) { Form2 frm = new Form2(); frm.Show(); this.Hide(); } form2 's FormClosed event: private void Form1_FormClosed(object sender FormClosedEventArgs e) { Form1 t = new Form1 (); t.Show(); }

Koteswararao Mallisetti · Answer

with out using mdi this is it solve? i want separate process from here that is requirement of me

Jaish Mathews · Answer

Hi THis is expected behaviour. Beacuse you defined Form2 object inside Form1 i.e. Form2 object scope and life is within Form1 only. So once Form1 closed all objects inside it will be released including Form2 object. That's why Form2 is closing automatically. In such scenarios you need to assign a single form from which each form can be loaded. You can use MDI form for this purpose. Here also once MDI form closed all other forms will be closed automatically it's expected behaviour.