openFileDialog to brows a folder if a program is running

Question

Hi Using openFileDialog would like to set a condition to check if a specific program is running or not. if it's running then openFileDialog will set the initial directory to a specific folder for that program otherwise it will go to another directory else it will open the C: directory Example: If Windows media player is running then openFileDialog will open/set the directory of C>>Users>>username>>My Music folder if Windows media player is not running it will set/open My documents else it will open the C: Directory

Sunny Sharma · Answer

Hi Hind Nazim Add a reference to System.Diagnostics and use the code below: ----------------------------------------------------------------- OpenFileDialog ofd = new OpenFileDialog (); Process [] pname = Process .GetProcessesByName( wmplayer ); if (pname.Length == 0) ofd.InitialDirectory = @C:\DefaultPath ; else ofd.InitialDirectory = @C:\Users\username\My Music ; // I assume this exist on target system. ------------------------------------------------------------------- Hope it helps! Happy Coding :)

Sunny Sharma · Answer

Hi Hind Nizam Sorry to make you wait a while please go through this post: http://www.c-sharpcorner.com/UploadFile/370e35/basedirectory-vs-currentdirectory-in-C-Sharp/ I hope it will help you understand this subject in a better way. Share your code what you've tried so far input(s) and expected output if still have issues. Happy Coding :)

Hind Najim · Answer

Hi Sunny Kumar I'm still struggling with this. Don't know how to do it.

Hind Najim · Answer

Hi Sunny Kumar Thanks for replying my question but I'm trying to debug it gives the path of Microsoft Visual studio not my running application path. Not sure. How to set the initial directory to be read automatically with BaseDirectory = AppDomain.CurrentDomain.BaseDirectory; string CurrentDirectory = Environment.CurrentDirectory; Process [] pname = Process .GetProcessesByName( ProcessName ); if (pname.Length == 0) ofd.InitialDirectory = @C:\DefaultPath ; else ofd.InitialDirectory = @C:\Users\username\MyApplication\Project2 ; // I want this to be read automatically instead of assigning the To explain more my question I'm working on windows form application and I have a browse button.. I have also an application (software) that creates project similler to the visual studio. this software usually needs to be running if I need to start my windows form application. If I created a project and saved with a name project2 and later I opened this project2 to read some files which are being saved under project2 folder how to code the browse button to go directly to my software directory and open folder project2 so that I can select some files from there. the task manager shows my running software under processes tab and under application tab you'll find the path of the folder project2. Can you help me on this plz

Sunny Sharma · Answer

Hi Hind Nizam I'm not pretty sure about what does it mean-  I'm working on a project which is running inside application but I assume it that you want to get the Directory in which your current application is running right? If yes the do it like this: string BaseDirectory= AppDomain .CurrentDomain.BaseDirectory; // it will give you the directory where your exe file resides. string currentDirectory= Environment .CurrentDirectory; it will give you the current directory under which your exe file is running. Don't get confused with these both they are quite different. Suppose your application path is  C:\Users\username\MyApplication\myProject . It may be that the .exe file is being called from some other location (let it be C: ) in command line or else so in that case the currentDirectory would be C: but the Base directory would always be C:\Users\username\MyApplication\myProject. I Hope I answered your question. Happy Coding :)

Hind Najim · Answer

Hi Sunny Kumar Two more question please. Suppose I'm working on a project which is running inside application and I need to open some files (related to this specific project) How to get the directory / path of that project. previously I asked if a program is running so that you checked the process and you set the initial directory (code below) OpenFileDialog ofd = new OpenFileDialog (); Process [] pname = Process .GetProcessesByName( wmplayer ); if (pname.Length == 0) ofd.InitialDirectory = @C:\DefaultPath ; else ofd.InitialDirectory = @C:\Users\username\My Music ; So I need something like this: @C:\Users\username\MyApplication\myProject(project4) // but this will be detected automatically based on which project that I'm currently working on. So I need to check first if my program is running and then get the path of my project automatically so that when openFileDialog runs it will go automatically to my project folder (which is one of multiple saved projects) i need to do same also but with folderBrowserDialog

Hind Najim · Answer

Cool ... Thanks Sunny Kumar!