Opening a form by clicking the button in another form

Question

Hello I try from one form by clicking the button to open another form. I put this code but nothing happens: private void button1_Click( object sender EventArgs e) { Izvest frm = new Izvest (); frm.Show(); } Can anybody tell me please where is my error. The second form's name is Izvest. Thanks.

Vulpes · Answer

It looks to me as though the button1_Click eventhandler is not being entered though you will know for sure if you put a MessageBox.Show() in there and nothing shows up as Sam said. The most likely reason is that it's not wired up to the event i.e. you've added the skeleton handler manually rather than via the designer. To test this theory place the following line in the form's constructor - immediately after InitializeComponent() - and see if it works then: button1.Click += button1_Click;

Sam Hobbs · Answer

For what it is worth I don't consider the points to be important but the words help. I appreciate that you said that we all helped and I agree with that.

Nel · Answer

You all did. Thank you to all of you who tried to help me.

Sam Hobbs · Answer

Did I not lead you to the answer? Do you think I did not help at all? Should I stop trying to help?

Nel · Answer

Yes button1_Click eventhandler is not being entered  thanks Vulpes

Sam Hobbs · Answer

I am sorry but I don't really understand what you are saying that happened when you used a breakpoint. The important thing is that the form's constructor was not executed correct? Try this. First put a MessageBox at the end (after the frm.Show()) of the button1_Click method. Then put a breakpoint on the first line (Izvest frm = new Izvest()) of the button1_Click method and then debug with that. Assuming that the breakpoint is hit press F5 when it is hit. After that you should see the MessageBox. Let us know what happens from that.

Nel · Answer

I tried with ShowDialog(this) but nothing happens

Nel · Answer

Here is what I got after debugging: At Izvest.cs line 17 character 13 ('Bl_jt.Izvest.Izvest()'line 3) The brakepoint will not currently be hit. No symbols have been loaded for this document.

Sam Hobbs · Answer

The code in your original post should work. Do you know how to use the debugger? You should put a breakpoint in the constructor for Izvest then debug the program. Do you know what I mean by constructor? You can put a breakpoint in the constructor (such as the line that calls InitializeComponent()) by going to (putting the cursor in) that line and pressing F9. A red ball will appear in the left margin. Then press F5. If when you click the button the debugger stops at the breakpoint then that gives us a big clue. If it does then just press F5 a second time close the program and post a reply here telling us that it did that. If the debugger does not stop at the breakpoint then post a reply here telling us that it did not.

Vulpes · Answer

Try opening the form modally with the owner set to the current form to ensure it doesn't appear behind the latter: Izvest frm = new Izvest(); frm.ShowDialog(this);

Nel · Answer

HEre is the code of the second form: public partial class Izvest : Form { public Izvest() { InitializeComponent(); } }

Om prakash Singh · Answer

Please check and revert that the form Izvest defines the class Izvest and have a constructor Izvest() If you can please send me the code of second page.

Nel · Answer

om: I tried this but doesn't work again. Priya: I saw the code but the code I need is the same like mine. I still have the problem

Priya Linge · Answer

Hi I did samething Second form open by button click. private void button1_Click(object sender EventArgs e) { Form2 fr = new Form2(); fr.Show(); } Please see attached file. Hope this will help you. Thanks.

Om prakash Singh · Answer

Private void button1_Click( object sender EventArgs e) { Izvest frm = new Izvest (); frm.Activate(); frm.BringToFront(); frm.Show(); }