random is not working(c#)

Question

Hi, I used Random class for get random numbers, but it bring me a same number every time. Here is my code: Random rnd = new Random (); newArr[j++] = ( char )(rnd.Next(65, 122)); any ideas? thanks.

sara shats · Answer

Thank you so much!

Niradhip Chakraborty · Answer

try this: protected void Page_Load(object sender, EventArgs e) { int intreturnValue = RandomNumber(100000, 999999); } private int RandomNumber(int min, int max) { Random random = new Random(); return random.Next(min, max); }

Vimal Kandasamy · Answer

one small change... put Random object creation before the for loop like below. Random rnd = new Random(); for (int i = 0, j = 0; i { newArr[j++] = originalArr[i]; for (int k = 0; k { newArr[j++] = (char)(rnd.Next(65, 122)); } }

sara shats · Answer

I am trying to put 2 random chars between every char in my Array for ( int i = 0, j = 0; i { newArr[j++] = originalArr[i] ; for ( int k = 0; k { Random rnd = new Random (); newArr[j++] = ( char )(rnd.Next(65, 122)); } } The original string was "sara" the result is "sHHaHHrHHaHH" I saw in the MSDN help a method: Math.Randomize, (in c# methods), but I can't use it. What can I do? thanks a lot!

Vimal Kandasamy · Answer

can you post the part of code which will get, store & use random values... it may help you to fix the problem

sara shats · Answer

I can't find any problem or mistake in my code, it can be an Application error? or maybe missing any 'using' (it's asp.net Application whis c# code)

Steve · Answer

Are you just trying to get a random number? or are you trying to throw a random number into an array...? just random number.. Random myrandom = new Random(); int number = myrandom.Next(min value, max value); for an array... Random myrandom = new Random(); int number = myrandom.Next(min value, max value); int[] myarray = new int[number];

Vimal Kandasamy · Answer

hi, for me it shows different chars. i execute your code as Random rnd = new Random(); Console.WriteLine( (char)(rnd.Next(65, 122))); Console.WriteLine((char)(rnd.Next(65, 122))); output is 1st time R h 2nd Y g 3rd Q j problem may be in your code.

random is not working(c#)

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Answers (8)