Regex on 05-02-2015

Question

Hello All I want to break the strings by using the Regular Expression: String1:(909_DIAGNOSEDOSE_PLUS_VORSERIE + (5DF_GESCHWINREGSTOPGOFKT 5AT_DRIVING_ASSISTANT_PLUS (5DP_PARKASSISTENT + (G032 G038 205_AUTOMATIK 2TB_SPORT_AUTOMATIK_GETRIEBE 2TE_AUTOMATIC_GETRIEBE_MIT_SCHALTWIPPEN)) 5DV_PARKASSISTENT_PLUS_ARBEITSNAME)) Output: 909_DIAGNOSEDOSE_PLUS_VORSERIE (5DF_GESCHWINREGSTOPGOFKT 5AT_DRIVING_ASSISTANT_PLUS (5DP_PARKASSISTENT + (G032 G038 205_AUTOMATIK 2TB_SPORT_AUTOMATIK_GETRIEBE 2TE_AUTOMATIC_GETRIEBE_MIT_SCHALTWIPPEN)) 5DV_PARKASSISTENT_PLUS_ARBEITSNAME)) Thanks in Advance Jithendra Pasala

Vulpes · Answer

Try this: using System; using System.Text.RegularExpressions; class Program { static void Main() { string text = (909_DIAGNOSEDOSE_PLUS_VORSERIE + (5DF_GESCHWINREGSTOPGOFKT 5AT_DRIVING_ASSISTANT_PLUS (5DP_PARKASSISTENT + (G032 G038 205_AUTOMATIK 2TB_SPORT_AUTOMATIK_GETRIEBE 2TE_AUTOMATIC_GETRIEBE_MIT_SCHALTWIPPEN)) 5DV_PARKASSISTENT_PLUS_ARBEITSNAME)); string regExp = @^$(\w+) \+ (.*)$$; Match m = Regex.Match(text regExp); for(int i = 1; i { Console.WriteLine(m.Groups[i].Value); Console.WriteLine(); } Console.ReadKey(); } } Note that the second output will have just one closing parenthesis (not two) with this code which I suspect is what you really want here: 909_DIAGNOSEDOSE_PLUS_VORSERIE (5DF_GESCHWINREGSTOPGOFKT 5AT_DRIVING_ASSISTANT_PLUS (5DP_PARKASSISTENT + (G032 G038 205_AUTOMATIK 2TB_SPORT_AUTOMATIK_GETRIEBE 2TE_AUTOMATIC_GETRIEBE_MIT_SCHALTWIPPEN)) 5DV_PARKASSISTENT_PLUS_ARBEITSNAME)