RegOpenKeyEx(HKey sKey 0 KEY_READ k)

Question

Hi! I use advapi32.dll and function lRet = RegOpenKeyEx(HKey_, sKey, 0, KEY_READ, k) for working in my register. In VB6 it work correctly, but in vb.net lRet = 5611065534578775. All parameters in vb6 and vb.net are the same.What's my mistake? Or where can I see the error description?

Andrey · Answer

Thanks. This is exactly what I need.

Alan · Answer

This is the suggested signature for calling that API function from VB.Net which I've taken from the P/Invoke.Net website: Declare Auto Function RegOpenKeyEx Lib advapi32.dll ( ByVal hKey As IntPtr ByVal lpSubKey As String ByVal ulOptions As Integer ByVal samDesired As Integer ByRef phkResult As Integer ) As Integer The most likely reason that you're having a problem is that the parameters and return type which had the Long type in VB6 will now require the Integer type in VB.Net. This is because Integer and Long were 2 and 4 byte integers in VB6 but are respectively 4 and 8 byte integers in VB.Net.

RegOpenKeyEx(HKey, sKey, 0, KEY_READ, k)