Regular Expression please..

Question

Hello All I want to break the strings by using the Regular Expression: String1:(2VH_AKTIVLENKUNG_UND_HSR + ALLRAD + !(111_HIGH_SECURITY) + (B47D20 + G011 B47D20 + G012 B48B20 + G011)) + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) String2:(2VH_AKTIVLENKUNG_UND_HSR + !(ALLRAD) + !(111_HIGH_SECURITY) + (B47D20 + G011 B47D20 + G012 B48B20 + G011)) + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) Output for string1: 2VH_AKTIVLENKUNG_UND_HSR + ALLRAD + !(111_HIGH_SECURITY) + B47D20 + G011 + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) 2VH_AKTIVLENKUNG_UND_HSR + ALLRAD + !(111_HIGH_SECURITY) + B47D20 + G012 + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) 2VH_AKTIVLENKUNG_UND_HSR + ALLRAD + !(111_HIGH_SECURITY) + B48B20 + G011 + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) Output for string2: 2VH_AKTIVLENKUNG_UND_HSR + !(ALLRAD) + !(111_HIGH_SECURITY) + B47D20 + G011 + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) 2VH_AKTIVLENKUNG_UND_HSR + !(ALLRAD) + !(111_HIGH_SECURITY) + B47D20 + G012 + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) 2VH_AKTIVLENKUNG_UND_HSR + !(ALLRAD) + !(111_HIGH_SECURITY) + B48B20 + G011 + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) Thanks in Advance Jithendra Pasala

Vulpes · Answer

Try the following: using System; using System.Text.RegularExpressions; class Test { static void Main() { string[] inputs = { (2VH_AKTIVLENKUNG_UND_HSR + ALLRAD + !(111_HIGH_SECURITY) + (B47D20 + G011 B47D20 + G012 B48B20 + G011)) + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) (2VH_AKTIVLENKUNG_UND_HSR + !(ALLRAD) + !(111_HIGH_SECURITY) + (B47D20 + G011 B47D20 + G012 B48B20 + G011)) + !(ZSWX_ZAHNSTANGENWECHSEL_XSTEER) }; string re = @^$(.*)\(([^!]*?.*?)${2}(.*)$; foreach(string input in inputs) { Match m = Regex.Match(input re); string str1 = m.Groups[1].Value; string[] split2 = Regex.Split(m.Groups[2].Value @\s*); string str3 = m.Groups[3].Value; foreach(string s2 in split2) { Console.WriteLine({0}{1}{2} str1 s2 str3); } Console.WriteLine(); } Console.ReadKey(); } }