Rethow exception in c#

Question

Hi What happens when we rethrow an exception in the catch who catches that exception. can anybody give me the example. thanks vinod .

Vulpes · Answer

As there's no method earlier in the call stack than the Main() method the exception cannot be caught and so the application would terminate with a DivideByZeroException. However in the following version there's an outer try/catch statement which can catch the rethrown exception: static void Main() { int x y z; try { try { x = 1; y = 0; z = x/y; } catch(DivideByZeroException) { throw; } } catch(DivideByZeroException ex) { Console.WriteLine(ex.Message +  Caught in outer try statement); }

Vulpes · Answer

When you rethrow an exception it's caught in: 1. A catch block in an enclosing try statement in the same method if there is one or if there isn't : 2. By a catch block in a try statement in a method earlier in the call stack. In the case of 2. the call stack is unwound until a method is found which contains a catch block which can handle the exception. If there is no such method then the exception will cause the application to terminate. Here's a simple example. Although a DivideByZero exception occurs in SomeMethod it's rethrown and caught instead in the Main method from which SomeMethod is called: using System; class Program { static void Main() { try { SomeMethod(); } catch(DivideByZeroException ex) { Console.WriteLine(ex.Message +  Caught in Main() method); } Console.ReadKey(); } static void SomeMethod() { int x y z; try { x = 1; y = 0; z = x/y; } catch(DivideByZeroException) { throw; } } }

vinod kumar · Answer

Hi Vulpes Thanks for the replay.It helped me in understanding exception handling. Thanks.

vinod kumar · Answer

Hi Vulpes What happens in the code below when catch rethrows exceptiondoes it is unhandled. static void Main() { int x y z; try { x=1; y=0; z=x/y; } catch(DivideByZeroException) { throw; } } Thanks.