1
Answer

ScloorViewer repeat button is going to lost sometimes?

Sumit Kumawat

Sumit Kumawat

12y
1.2k
1
hi all,
i am using the listview control in my application, inside the listview my scrollbar "Repeatbutton" is going to lost some times.
i am not getting why this is happneing.
plz help me out..

Attachment: testt.zip

Answers (1)
0
Sam Hobbs
NA 28.7k 1.3m 13y
The easiest and most reliable way is to create an auto-incrementing database field and then when you insert a new customer, get the number of the new customer record. The number will be only the number part; it would not include the "E" part. The E could be added whenever it is needed for formatting. Will the "E" part ever be something other than E? If so, then what is the meaning of it?
0
magesh manavalan
NA 244 423.5k 13y
Hi dear thanx for ur co operations and help ur codings.


Thanks&Regs

Magesh.A
0
Satyapriya Nayak
NA 53k 8m 13y
Hi Magesh,



 

Create table employee(empid varchar(50),empname varchar(50),sal int)

 
Default.aspx code

 

<%@ Page Language="C#" AutoEventWireup="true"  CodeFile="Default.aspx.cs" Inherits="_Default" %>

 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

 

<html xmlns="http://www.w3.org/1999/xhtml">

<head runat="server">

    <title>Untitled Page</title>

</head>

<body>

    <form id="form1" runat="server">

    <div>

  

        <asp:Label ID="Label1" runat="server" Text="EmpId" Font-Bold="True"

            Width="100px"></asp:Label>

    <asp:TextBox ID="txt_empid" runat="server"></asp:TextBox><br />

    <asp:Label ID="Label2" runat="server" Text="EmpName" Font-Bold="True" Width="100px"></asp:Label>

    <asp:TextBox ID="txt_empname" runat="server"></asp:TextBox><br />

    <asp:Label ID="Label3" runat="server" Text="Salary" Font-Bold="True" Width="100px"></asp:Label>

    <asp:TextBox ID="txt_sal" runat="server"></asp:TextBox><br />

    </div>

  

    <asp:Button ID="btn_insert" runat="server" onclick="btn_insert_Click"

        Text="Insert Data" /><br />

    <asp:Label ID="Label4" runat="server"></asp:Label>

  

    </form>

</body>

</html>

 
Default.aspx.cs code

 

using System;

using System.Configuration;

using System.Data;

using System.Linq;

using System.Web;

using System.Web.Security;

using System.Web.UI;

using System.Web.UI.HtmlControls;

using System.Web.UI.WebControls;

using System.Web.UI.WebControls.WebParts;

using System.Xml.Linq;

using System.Data.SqlClient;

public partial class _Default : System.Web.UI.Page

{

    string strConnString = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString;

    string str;

    SqlCommand com;

    int count;

    protected void Page_Load(object sender, EventArgs e)

    {

        SqlConnection con = new SqlConnection(strConnString);

        str = "select count(*) from employee";

        com = new SqlCommand(str, con);

        con.Open();

        count = Convert.ToInt16(com.ExecuteScalar()) + 1;

        txt_empid.Text = "E000" + count;

        con.Close();

    }

    protected void btn_insert_Click(object sender, EventArgs e)

    {

        SqlConnection con = new SqlConnection(strConnString);

        con.Open();

        str = "insert into employee values('" + txt_empid.Text.Trim() + "','" + txt_empname.Text.Trim() + "'," + txt_sal.Text.Trim() + ")";

        com = new SqlCommand(str, con);

        com.ExecuteNonQuery();

        con.Close();

        Label4.Text = "Records successfully Inserted";

    }

}

Thanks
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