some questions in C Programming need answers for my mid exam I really need help.

Question

How do we find out in C if a number is even? I answer with this: if(number %2==) ________________________________________ I have only less than 48 hours before my exam start I have to know the answers of these questions due to my teacher foucs on them for my mid semester exam. wish me luck :( Regards __________________________ Assuming an int i already exists write a for loop that prints 10 %'s on one line one at a time. I answer with this: for (i=0;i Printf(% ); } _______________________________________ The % operator can be applied to two integers what is the result of 12 % 5? _______________________________________ #include int i j; char d; int main() { d = 'A'; for (i=0; i printf(%*c 5-i d); for (j=1; j printf(B); } printf( ); } } Why we got answer like that I know because we looped it but how it functionally is working through the program: I got output like this: A AB ABB ABBB ABBBB _________________________ i AM CONFUAED WITH THIS ONE TOO Write a C program that contains a void function print_a. The function produces this pattern on the screen: A A A A A AAAAA A A A A ____________________ What does robust mean when applied to software? _____________________________ The following code which was written to produce 10 lines of output each containing the word 2up contains 5 errors. Mark each one of them with a circle and describe why it is an error. [10] void 2up(void); int i; int main() { for (i:=0; i 2up(); } } void 2up(void) { printf(2up ); } ______________________________ Write a C program that contains a global integer variable number and a void functionprint_number. The function prints the value stored in number. The output is right justified with leading zeros in a field width of 10 followed by a newline. e.g. if number has the value 134 then the function print_number produces: 0000000134 The main function sets number to 134 and then calls the print_number function. it does not work: #include int number; void print_number() { printf(%010d number); } void main {) { number=134; print_number(); system(pause); } ___________________

Vulpes · Answer

Here's what I think the answers are to the remaining questions : The second one should be : for (i=0;i printf(%%); } You need to 'escape' the % by doubling it bearing in mind it's normally used to specify a format in the printf() statement. So %% prints just one %. ____________________________________________________________________________________________________ The answer to the third one (12 % 5) is 2 because that's the remainder when 12 is divided by 5. ____________________________________________________________________________________________________ The fourth question works like this: As 'c' is preceded by * it formats the character d (which contains 'A') in a field (5 - i) characters wide. So when i is 0 then 'A' is preceded by 4 spaces when i is 1 'A' is preceded by 3 spaces and so on. 'B' is then written between 1 and 'i' times. So when 'i' is 0 'B' is written 0 times when 'i' is 1 it's written once and so on. A space is then printed before the next combination. ____________________________________________________________________________________________________ As the question doesn't ask you to do any fancy loops just do it normally: void print_A(void); int main() { printf( A
); printf( A A
); print_A(); printf(AAAAA
); print_A(); print_A(); } void print_A(){ printf(A A
); } ____________________________________________________________________________________________________ Software is said to be robust if performs well not just under normal conditions but under abnormal conditions as well. ____________________________________________________________________________________________________ The errors are : 2up - identifiers can't start with a number; change it to twoup say In the 'for' statement there are 3 errors: There shouldn't be a colon after 'i' 1++ should be i++ There shouldn't be a semi-colon at the end of the 'for' statement - otherwise 2up will only print once. In the 2up function printf(2up ); should be printf(2up
); to print on separate lines. ____________________________________________________________________________________________________ Try: #include int number; void print_number() { printf(%010d
number); /* now prints a new line after the number */ } void main() /* left parenthesis instead of left curly brace */ { number=134; print_number(); system(pause); }

Jeet gupta · Answer

answer about your question How do we find out in C if a number is even? Ans: if(number %2==0) printf(Number is Even)

some questions in C Programming need answers for my mid exam, I really need help.