Split an array like below.

Question

arr[]={ 12 34 56 67 65 43 78 88 43 28....n} split=2 sum=2 then the result array should be like this. res[0]=47 //1+2+5+6+6+5+7+8+4+3 res[1]=53 //3+4+6+7+4+3+8+8+2+8 Please help me to do this.

Midhun T P · Answer

Hi Please try below code - int[] arr = { 1 2 3 4 5 6 6 7 6 5 4 3 7 8 8 8 4 3 2 8}; int split = 2; int sum = 2; int[] res = new int[split]; int i = 0; int j = 1; for (int k = 0; k { res[i % split] = res[i % split] + arr[k]; if (k == ((j * sum) - 1)) { j++; i++; } } foreach (var v in res) { Console.WriteLine(v); }

Manas Mohapatra · Answer

Try like below: int [] arr = { 1 2 3 4 5 6 6 7 6 5 4 3 7 8 8 8 4 3 2 8 }; int [] tempArr = new int [2]; int counter = arr.Length / (2 + 2); // SplitNo(2) + no of elements(2) = 4 for ( int idx = 0; idx { tempArr[0] += arr[idx * 4]; tempArr[0] += arr[(idx * 4 )+ 1]; tempArr[1] += arr[(idx * 4) + 2]; tempArr[1] += arr[(idx * 4) + 3]; }

Rajeev Punhani · Answer

Hi Pruthvi Please have a look at the below snippet. using System; using System.Linq; public class Program { public static void Main() { int []arr={12345667654378884328}; int index=0sum1=0sum2=0; while (index { sum1+=arr.Skip(index).Take(2).Sum(); sum2+=arr.Skip(index+2).Take(2).Sum(); index+=4; } Console.WriteLine(sum1); Console.WriteLine(sum2); } } If the above solution is helpful then accept the answer.

Ifour Hiren · Answer

static void Main(string[] args) { if (args != null) { int argument =Convert.ToInt32(args[0]); int[] arr = { 1 2 3 4 5 6 6 7 6 5 4 3 7 8 8 8 4 3 2 8 }; int index = 0; int[] sumarry= new int[argument]; while (index < arr.Length) { for (int i = 0; i < argument; i++) { sumarry[i] += arr.Skip(index).Take(argument).Sum(); index += argument; } } for (int i = 0; i < argument; i++) { Console.WriteLine(sumarry[i]); } } } above code helps you to make it working.

Rajeev Punhani · Answer

HiPruthvi Please see the below snippet. using System; using System.Linq; public class Program { public static void Main() { int []arr={12345667654378884328}; int split=0; Console.WriteLine( PleaseEnterTheSplit ); split=Convert.ToInt32(Console.ReadLine()); GetSum(arrsplit); } protected static void GetSum( int []arr int split) { int index=0; int []sum= new int [split]; while (index { for ( int i=0;i { sum[i]+=arr.Skip(index).Take(split).Sum(); index+=split; } } for ( int i=0;i { Console.WriteLine(sum[i]); } } }

Tharu Manickavasagar · Answer

This might help you. int []arr={123124561732113452}; Split(3arr); private int[] Split( int splitCount int []arr) { int [] resultArr= new int [splitCount]; int total=0; int k=0; int i=1; while (i { k=i-1; for ( int m=1;m { for ( int n=1;n { total+=arr[k]; k++; } resultArr[m-1]+=total; total=0; } i+=(splitCount*splitCount); } return resultArr; }

Tharu Manickavasagar · Answer

You can do like this. int []arr={12345667654378884328}; int []resultArr= new int [2]; int firstTotal=0secondTotal=0; for ( int i=1;i<arr.Length;i=i+4) { firstTotal+=arr[i-1]+arr[i]; if (i+2<arr.Length) secondTotal+=arr[i+1]+arr[i+2]; } resultArr[0]=firstTotal; resultArr[1]=secondTotal;

Pruthvi Patel · Answer

Thanks for reply but as you use 2 variable like sum1sum2temparr1temparr2 and doing it sum is not solution. I want that if split is 3 then there should be 3 variable sum1sum2sum3 and like wise. I hope you will understand this problem and help me.

Pruthvi Patel · Answer

Thanks to all for reply and help.