Split and sum array element like below.

Question

arr[]={13246788}; split=2; // the arr[] will be divide in 2(no of splits) parts each with equal elements skip=1; // skip is no of element to be skipped. size of res[] should be accordingly. then res[0]=3 //1+2 res[1]=7 //3+4 res[2]=14 //6+8 res[3]=15 //7+8 split=123...n skip=123...n arr[]={123...n} elements This should be dynamically. Please help me to do this. Thanks

Manas Mohapatra · Answer

Try with below code: int [] arr = { 1 3 2 4 6 7 8 8 }; int split = 2; int counter1 = 0; int counter = arr.Length / (split); int [] tempArr = new int [counter]; for ( int idx = 0; idx { if (idx % split == 0) { counter1 = idx * split; } else { counter1 = idx * split - 1; } tempArr[idx] = arr[counter1] + arr[counter1 + split]; }

Pruthvi Patel · Answer

Hi manas Please help me in this. In above code there is skip=1 only. but if i am want to change it then how to do this? arr[]={ 123456 789101112 896542 } split=3 skip=2 res1[0]= 5 //1+4 res1[1]=7 //2+5 res1[2]=9 //6+3 res1[3]=17 //7+10 res1[4]=19 //8+11 res1[5]=21 //12+9 res1[6]=13 //8+5 res1[7]=13 //9+4 res1[8]=8 //6+2 Like this where skip and split can be 123..n Please Please Help me to do this as i have to use this in my college project work.Please

Pruthvi Patel · Answer

HiManas In above requirement skip=1 but if i want to change it then how to do this. Please help me to do this

Manas Mohapatra · Answer

Updated previous answer please check..

Pruthvi Patel · Answer

ManasThanks help can you use the variable(splitskip) in this code.So i can able to change accordingly my requirement.