static field initialization how takes place

Question

When you initialize a static variable the initialization always takes place before any reference is made to that variable I `am not understanding how this sentence is true please give an example in support of this sentence.

Manas Mohapatra · Answer

Please go through below example: Here there are three classes Test First second. In Test class it displays output which depends on First and Second. First class declares a static variable called X which calls static function of class Test . In same way class Second declares a static variable called Y which calls static function of class Test using System; class Test { static void Main() { Console.WriteLine({0} {1} Second .Y First .X); } public static int F(string s) { Console.WriteLine(s); return 1; } } class First { public static int X = Test.F(First A); } class Second { public static int Y = Test.F(Second A); } Output: First A Second A 1 1 Because the execution of X's initializer and Y's initializer could occur in either order; they are only constrained to occur before the references to those fields.