store and read DateTime

Question

Hello I have to store DateTime.Now value in UInt32 variable. This variable will send with an EtherPacket extention. This field in packet will monitor as 32 bit : Nov 11 2004 10:13:52.-660770640 My question is how can i store DateTime.Now in in UInt32 variable and read DateTime from it ? regards

oneneno · Answer

Hello So i have get it: TimeSpan ts = DateTime.Now - new DateTime( 1900 1 1 0 0 0 0 ); m_new_reg_time = (UInt32)ts.TotalSeconds; m_new_reg_rand = (UInt32)ts.TotalMilliseconds; but Ethereal show the time 1 hour later from my systemtime: Etherreal : Jan 4 2005 18:23:09.14353465 My systemtime: Jan 4 2005 17:23:09.14353465 How can i change it to correct time by sending throuth ethernet ? best regards

oneneno · Answer

All i have to do is to implement this protocol:  Identification field MUST set the to a 64-bit value formatted as specified by the Network Time Protocol. The low-order 32 bits of the NTP format represent fractional seconds and those bits which are not available from a time source SHOULD be generated from a good source of randomness.

oneneno · Answer

Hi Kannan It works fine ! My problem is i dont khow to convert this C code segment into C# : // high-order 32 bits: time in seconds from year 1900 // low-order 32 bits: fractional seconds (1/256 sec resolution // i.e. 8 bits used) and the last bits random int new_reg_time; unsigned int new_reg_rand; static int last_reg_time = 0; static unsigned int last_reg_rand = 0; struct timeval tv; ....... gettimeofday(&tv NULL); new_reg_time = tv.tv_sec + mn.clock_correction; new_reg_rand = ((tv.tv_usec * 256 / 1000000) id[0] = htonl(new_reg_time + UNIX_NTP_DIFF); req->id[1] = htonl(new_reg_rand); last_reg_time = new_reg_time; last_reg_rand = new_reg_rand; Do you have an idea ? regards

oneneno · Answer

Thank a lot ! Kannan I will try it out and tell you later !

eyes · Answer

Hi U can also separate Int64 into two UInt32 and then send through EtherPacket . . . After that combine both to get date time value . . . // // Take the current time as follows . . . // Int64 now1 = DateTime.Now.Ticks ; // // Separate the Int64 into two separate UInt32. // ie First 32 bits in one UInt32 variable and Last 32 bits into another UInt32 variable . . . // UInt32 f1 = ( UInt32 ) ( now1 >> 32 ) ; UInt32 s1 = ( UInt32 ) ( ( now1 > 32 ) ; // // Send across with the EtherPacket . . . // // After receiving combine the both UInt32 into single Int64 . . . // Int64 f2 = ( Int64 ) f1 << 32 ; Int64 s2 = s1 ; Int64 now2 = f2 | s2 ; // // Finally construct the date time value . . . // DateTime now = new DateTime ( now2 ) ; Hope this will help u . . . Cheers Kannan T PS: This idea is given by my friend Sabu. Thanks Sabu ! ! !

eyes · Answer

Hi U can solve using Int64 . . . First convert to Int64 as below Int64 now64 = DateTime.Now.Ticks ; From this now again construct the DateTime as below DateTime nowDT = new DateTime ( now64 ) ; Is it Ok ? Cheers Kannan T