System.Drawing - Parameter is not valid

Question

using code: byte[] toBytes = Encoding.ASCII.GetBytes(objgroupconfereneResponse.groups[i].grpIcon.ToString()); if (toBytes != null) { MemoryStream ms = new MemoryStream(toBytes); ms.Position = 0; picboxserver.Image = Image.FromStream(ms); } please suggest me how to resolve it.

Yogesh Vedpathak · Answer

var request = webRequest.Create(  ); using (var response= request.GetResponse()) using (var stream =response.GetResponseStream ()) { PictureBox.Image = Bitmap.FromStream(stream); }

Shefali Lahariya · Answer

Hi yogesh  PF the code: string img2 = http://13.228.146.249:8080/jcr/groups/629.png; byte[] toBytes = Encoding.ASCII.GetBytes(img2); if (toBytes != null) { MemoryStream ms = new MemoryStream(toBytes); ms.Position = 0; picboxserver.Image = Image.FromStream(ms); } picboxserver is picturebox type.

Yogesh Vedpathak · Answer

Hi Shefali  I think this problem is occured due to differnt format of image like jpegbmp Please can you share all function public static byte[] ImageToByte2(Image img) { using (var stream = new MemoryStream()) { img.Save(stream system.Drawing.Imaging.ImageFormat.png); return stream.ToArray(); } }

Shefali Lahariya · Answer

hi yogesh how to display image in picturebox getting this http://13.228.72.152:8080/jcr/groups/629.png url from server. buy i am getting Parameter is not valid error when we use below code.

Yogesh Vedpathak · Answer

First Explain What you are trying to Achieve ...? and use simple try catch block to handle exception ...

Shefali Lahariya · Answer

hi sagar i have tried this code getting same error.

Sagar Pandurang Kap · Answer

Try this :- ImageConverter imageConverter = new System.Drawing.ImageConverter(); Image image = imageConverter.ConvertFrom(byteArray) as Image;