Time Convertion

Question

Hi all my time format is '%Y-%m-%d %H:%M:%S' start_time = 2014-12-04 08:10:32 end_time = 2014-12-04 12:34:45 Here i want output like diff_time = 4.24 Thanks in advance...

Vignesh Mani · Answer

DateTime startTime = varValue DateTime endTime = varTime TimeSpan span = endTime . Subtract ( startTime ); Console . WriteLine ( Time Difference (seconds):  + span . Seconds ); Console . WriteLine ( Time Difference (minutes):  + span . Minutes ); Console . WriteLine ( Time Difference (hours):  + span . Hours ); Console . WriteLine ( Time Difference (days):  + span . Days );

Rajeev Punhani · Answer

DateTime start_time = Convert.ToDateTime(2014-12-04 08:10:32); DateTime end_time = Convert.ToDateTime(2014-12-04 12:34:45); TimeSpan t = end_time - start_time; //Here t will be the time difference in format HH:MM:ss .So output will be 04:24:13 Response.Write(t); //For getting in format what you expected just format timespan var res = String.Format({0}.{1}t.Hourst.Minutes); Response.Write( + res);

Upendra Pratap Shahi · Answer

TimeSpan time1 = TimeSpan.Parse(textBox1.Text); TimeSpan time2 = TimeSpan.Parse(textBox2.Text); TimeSpan difference = time1 - time2; int hours = difference.Hours; int minutes = difference.Minutes; or var first = new DateTime(2012 05 08 10 30 00); var second = new DateTime(2012 05 08 11 49 13); var diff = first - second; var hours = diff.Hours; var mins = diff.Minutes;

Vignesh Mani · Answer

string sDateFrom = 11:56:00; string sDateTo = 12:12:00; if (DateTime.TryParse(sDateFrom out dFrom) && DateTime.TryParse(sDateTo out dTo)) { TimeSpan TS = dTo - dFrom; int hour = TS.Hours; int mins = TS.Minutes; int secs = TS.Seconds; string timeDiff = hour.ToString(00) + : + mins.ToString(00) + : + secs.ToString(00); Response.Write(timeDiff); //output 16 mins in format 00:16:00 }