VB.NET and flipping bytes

Question

How would I code VB.NET to accept a string from a text box for example: 89302720304070539803 and then display: 98 03 72 02 03 04 07 35 89 30 Thanks much... Celldet

Celldet · Answer

Thank you so very much! I have changed it to VB.NET as indicated below. I will let you know of the results...Thanks again! Protected Sub Button1_Click(ByVal sender As Object ByVal e As EventArgs) Dim value As String = textbox1.Text.ToString() Dim ReturnValue As String =  Dim length As Integer = value.Length While length > 1 Dim cutValue As String = value.Substring(0 2) ReturnValue = ReturnValue +   + Reverse(cutValue) value = value.Substring(2 value.Length - 2) length = value.Length End While Label1.Text = ReturnValue End Sub Public Function Reverse(ByVal str As String) As String Dim len As Integer = str.Length Dim arr As Char() = New Char(len - 1) {} For i As Integer = 0 To len - 1 arr(i) = str(len - 1 - i) Next Return New String(arr) End Function

Manish Dwivedi · Answer

Hi U can do this by using this code. protected void Button1_Click( object sender EventArgs e) { string value = textbox1.Text.ToString(); string ReturnValue =  ; int length = value.Length; while (length > 1) { string cutValue = value.Substring(0 2); ReturnValue = ReturnValue +   + Reverse(cutValue); value = value.Substring(2 value.Length - 2); length = value.Length; } Label1.Text = ReturnValue; } public string Reverse( string str) { int len = str.Length; char [] arr = new char [len]; for ( int i = 0; i { arr[i] = str[len - 1 - i]; } return new string (arr); } Happy Coding!!