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Why does the compiler give error to my Code?

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Joe Wilson

Joe Wilson

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This is my code:
 
 

#include "stdafx.h"
#include <iostream>
#include <conio.h>
#include <stdio.h>
#define max 30

char pop(void);
void push(char);
int Isunder(void);
int Isover(void);
int prio(char);

int top=-1,i=0,j=0;
char stk[max];
char infix[max];
char postfix[max];

void main()
{
cout << "Please enter your expression in infix form :";
cin >> infix ;
for(i=0;infix[i]!='\0';i++)
{
switch(infix[i])
{
case '(' :

push( '(' );
break;

case ')' :

while(stk[top]!='(')
postfix[j++]=pop();


if (stk[top]=='(')
top--;

break;

case '/':
case '*':
case '+':
case '-':
case '^':
if (!Isunder())
{
if (prio(infix[i]) > prio(stk[top]) )
{
push(infix[i]);

}
else
{
postfix[j++]=pop();
push(infix[i]);

}

}
else
push(infix[i]);

break;

default :
postfix[j++] = infix[i] ;


}


}

while (!Isunder())
postfix[j++]=pop();

postfix[j]='\0';

cout << endl << "Your postfix expression is :" << postfix << endl ;


}

//// pop opertation
char pop()
{

if (!Isunder())
return stk[top--];

}

//// push operation

void push(char ch)
{
if (!Isover())
stk[++top]=ch;
else
cout << "Stack is full";
}
//// overflow

int Isover()
{

if (top == max-1)
return 1;
else
return 0;

}

//// underflow

int Isunder()
{

if (top == -1)
return 1;
else
return 0;

}
/////////////////////////////
int prio(char ch)
{
switch(ch)
{
case '(' :
return 1;
break;
case '-' :
return 2;
break;
case '+' :
return 3;
break;
case '*' :
return 4;
break;
case '/' :
return 5;
break;
case '^':
return 6;

}
}

 

Answers (1)