NP67 Dimensional Array

Question

Hi Guys

By means of counting the elements (below program) it is possible to predict number of elements in one-dimensional array prior to the execution of the program. And elements can be assigned as follows:

empID[0] = 15

empID[1] = 20

empID[2] = 5

In the three dimensional array though Length is 4 (below program) how can predict number of elements in. And how can elements be assigned. Anyone knows please explain.

Thank you

using System;

class MainClass

{

public static void Main()

{

int[] empID = new int[] { 15, 20, 5, };

int[, ,] empArray = new int[1, 2, 2];

Console.WriteLine("empID.Length = " + empID.Length);

Console.WriteLine("empArray.Length = " + empArray.Length);

}

/*

empID.Length = 3

empArray.Length = 4

*/

Maha · Answer

Thank you for the explanation Alan.

Alan · Answer

For some reason that link doesn't work but from your description in the same way that a two dimensional array can be used to represent points on a rectangular surface I imagine that a three-dimensional array is being used to represent points on the surface of a cube i.e. the third dimension represents one of the six sides. I'd have thought that strictly speaking a rectangular array was just a two dimensional array but the C# Specification does in fact use the term rectangular array to represent any non-jagged multidimensional array so I guess we can consider that as 'official' :)

Maha · Answer

Hi Guys http://en.csharp-online.net/All_about_Arrays_in_CSharp%E2%80%94Instantiating_a_One-Dimensional_or_Rectangular_Array In the above website Figure 14-5 shows the diagram of a cube to explain three-dimensional array. Cube edges representing the dimensions. My problem is if Dimension of the array exceeds the number of available edges in the cube how to represent in a cube. In such a situation if it is appropriate to call rectangular array. Anyone knows please explain. Thank you

Maha · Answer

Thank you for the explanation Alan.

Alan · Answer

In general if you have a 3 dimensional array such as the one below where xy and z are positive integers: int [ ] empArray = new int [x y z]; then the number of elements in the array is x * y * z. So in the case of this array: int [ ] empArray = new int [1 2 2]; there are 1 * 2 * 2 = 4 elements You could set these elements 'manually' as follows: empArray[0 0 0] = 20; empArray[0 0 1] = 30; empArray[0 1 0] = 40; empArray[0 1 1] = 50; If the initial values of each element are a function of x y and z then larger arrays would normally be initialized using three nested 'for' loops.