Open Form1 as new instance after successful operations on Fo

Question

I am having two forms as Form1 and Form2 on Form1 button click I am opening the form2 as follows

private Form2 form2; this.Hide(); form2.ShowDialog(); this.Show();

I have a back button and submit button on Form2 when I click on Back this is how I am showing Form1

this.Hide(); this.DialogResult = DialogResult.OK;

But when I submit the form I need to load the Form1 with new instance, this is what I tried but Form1 is showing multiple times

if (DialogResult.OK == MessageBox.Show("Installation was done", "Success", MessageBoxButtons.OK, MessageBoxIcon.Information)) { Form f1 = new Form ();    f1.Show(); this.Close(); }

Can some one help me

Attachment: WindowsFormsApplication2.zip

Dorababu Meka · Answer

Try the following codeon your Form1 button click event write the following private void button1_Click( object senderEventArgse) { form2.ShowData(textBox1.Text); form2.ShowDialog( this ); } In your Form2 submit click have the following code private void button2_Click( object senderEventArgse) { this .Owner.Hide(); this .Owner= new Form1( this ); this .Hide(); this .Owner.Show(); } Attached the code of the same

Salman · Answer

Hi. then at that time you need to close the form1. Thanks.

Devi · Answer

But when I close Form1 after that it is not exiting from the application

Salman · Answer

Hi. Goto Your Form2.cs and change the code like this private void button2_Click(object sender EventArgs e) { Form1 f2 = new Form1(this); this.Hide(); f2.ShowDialog(); this.Show(); } Thanks.